Admin
1
I need to round of a number (the input is guaranteed to be an integer & is positive) to the next multiple of 5.
I tried this:
int round = ((grades[j] + 2)/5) * 5;
However, this rounds off the number to the nearest multiple of 5.
Eg: 67 is rounded off to 65, not 70.
This is my solution using cmath::abs
int rounded = n + abs((n % denom) - denom);
You can change the denom with any other denomination you want
I have a function to round up:
def next(number, base):
temp = round(number / base) * base
return temp
you can use it for your case like this:
next(grade[j], 5)
and in function it will be:
temp = round(67 / 5) * 5
return temp #temp = 75
some case not using round but using ceil
Why so much of complication. Here is the code. Have a look.
vector<int> gradingStudents(vector<int> grades) {
int size = grades.size();
for(int i=0;i<size;i++)
{
if(grades[i]>40)
{
if((grades[i]+2)%5==0)
grades[i]=grades[i]+2;
else if((grades[i]+1)%5==0)
grades[i]=grades[i]+1;
}
else if(grades[i]>37&&grades[i]<40)
grades[i]=40;
}
return grades;
}