Extract src attribute from img tag using BeautifulSoup

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<div class="someClass">
    <a href="href">
        <img alt="some" src="some"/>
    </a>
</div>

I want to extract the source (i.e. src) attribute from an image (i.e. img) tag using BeautifulSoup. I use bs4 and I cannot use a.attrs['src'] to get the src, but I can get href. What should I do?

beautifulsoup python regex
4 Answers

You can use BeautifulSoup to extract src attribute of an html img tag. In my example, the htmlText contains the img tag itself but this can be used for a URL too along with urllib2.

For URLs

from BeautifulSoup import BeautifulSoup as BSHTML
import urllib2
page = urllib2.urlopen('http://www.youtube.com/')
soup = BSHTML(page)
images = soup.findAll('img')
for image in images:
    #print image source
    print(image['src'])
    #print alternate text
    print(image['alt'])

For Texts with img tag

from BeautifulSoup import BeautifulSoup as BSHTML
htmlText = """<img src="https://src1.com/" <img src="https://src2.com/" /> """
soup = BSHTML(htmlText)
images = soup.findAll('img')
for image in images:
    print(image['src'])

Python 3 : Updated on 2022-02-02

from bs4 import BeautifulSoup as BSHTML
import urllib

page = urllib.request.urlopen('https://github.com/abushoeb/emotag')
soup = BSHTML(page)
images = soup.findAll('img')

for image in images:
    #print image source
    print(image['src'])
    #print alternate text
    print(image['alt'])

Install modules if needed

# python 3
pip install beautifulsoup4
pip install urllib3
user_38082760

here is a solution that will not trigger a KeyError in case the img tag does not have a src attribute:

from urllib.request import urlopen
from bs4 import BeautifulSoup

site = "[insert name of the site]"
html = urlopen(site)
bs = BeautifulSoup(html, 'html.parser')

images = bs.find_all('img')
for img in images:
    if img.has_attr('src'):
        print(img['src'])
user_31998220

You can use BeautifulSoup to extract src attribute of an html img tag. In my example, the htmlText contains the img tag itself but this can be used for a URL too along with urllib2.

The solution provided by the most rated answer is not working any more with python3. This is the correct implementation:

For URLs

from bs4 import BeautifulSoup as BSHTML
import urllib3

http = urllib3.PoolManager()
url = 'your_url'

response = http.request('GET', url)
soup = BSHTML(response.data, "html.parser")
images = soup.findAll('img')

for image in images:
    #print image source
    print(image['src'])
    #print alternate text
    print(image['alt'])

For Texts with img tag

from bs4 import BeautifulSoup as BSHTML
htmlText = """<img src="https://src1.com/" <img src="https://src2.com/" /> """
soup = BSHTML(htmlText)
images = soup.findAll('img')
for image in images:
    print(image['src'])
user_47579930
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