How to make a script automatically restart itself?

user_6067779 0
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How do you make a python program automatically restart itself? So let's say there is a really simple program like:

var = input("Hi! I like cheese! Do you like cheese?").lower()
if var == "yes":
    print("That's awesome!")

Now, in a Python Shell, you would have to press either the Run button and then 'Run Module (F5)' or just the F5 key on your keyboard. That is the first time you run it. When the program ended, you would go back to your Cheese.py file and then press F5 to run the program again.

Everybody with me here? OK, so my question is, how do you make the program restart itself automatically without you having to manually do it?

python
5 Answers

I use terminal on my Mac to re-start some of my python scripts with the function below.

import subprocess  
def run_again(cmd):
    subprocess.call(["bash", "-c", "source ~/.profile; " + cmd])

Note: Don't forget the space character after "profile;" or the function may fail silently!

Then at the bottom of my script to be re-started:

if some_condition:  
    run_again("python my_script.py %s" % my_new_arguments)

For the original question about the cheese script:

if var != 'yes':  
    run_again("python my_cheese_script.py")
user_5128610

or you can try

$ chmod a+x "name".py

Then, you can run the script via

$ ./daemon.py

In such a situation, to restart the script, use the following code:

os.execv(__file__, sys.argv)

Otherwise, when you run the script via

$ python daemon.py

use this code:

os.execv(sys.executable, ['python'] + sys.argv)

Either way, do not forget to import the sys module

user_100817080

You can just use a shell script like test.sh and make sure in your linux terminal you chmod +x test.sh

As for the code:

#!/bin/bash

while :
do
  sleep 5
  gnome-terminal --wait -- sh -c "python3 myscript.py 'myarg1'"
done
user_12559560
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