How can I turn:
Person.all.pluck(:id, :name)
to
[{id: 1, name: 'joe'}, {id: 2, name: 'martin'}]
without having to .map every value (since when I add or remove from the .pluck I have to do he same with the .map)
How can I turn:
Person.all.pluck(:id, :name)
to
[{id: 1, name: 'joe'}, {id: 2, name: 'martin'}]
without having to .map every value (since when I add or remove from the .pluck I have to do he same with the .map)
If you use postgresql, you can use json_build_object function in pluck method:
https://www.postgresql.org/docs/9.5/functions-json.html
That way, you can let db create hashes.
Person.pluck("json_build_object('id', id, 'name', name)")
#=> [{id: 1, name: 'joe'}, {id: 2, name: 'martin'}]
There is pluck_all gem that do almost the same thing as pluck_to_hash do. And it claims that it's 30% faster. (see the benchmark here).
Usage:
Person.pluck_all(:id, :name)
If you have multiple attributes, you may do this for cleanliness:
Item.pluck(:id, :name, :description, :cost, :images).map do |item|
{
id: item[0],
name: item[1],
description: item[2],
cost: item[3],
images: item[4]
}
end
The easiest way is to use the pluck method combined with the zip method.
attrs_array = %w(id name)
Person.all.pluck(attrs_array).map { |ele| attrs_array.zip(ele).to_h }
You can also create a helper method if you are using this method through out your application.
def pluck_to_hash(object, *attrs)
object.pluck(*attrs).map { |ele| attrs.zip(ele).to_h }
end
Consider modifying by declaring self as the default receiver rather than passing Person.all as the object variable.
Read more about zip.
Here is a method that has worked well for me:
def pluck_to_hash(enumerable, *field_names)
enumerable.pluck(*field_names).map do |field_values|
field_names.zip(field_values).each_with_object({}) do |(key, value), result_hash|
result_hash[key] = value
end
end
end
I know it's an old thread but in case someone is looking for simpler version of this
Hash[Person.all(:id, :name)]
Tested in Rails 5.