What is the cleanest way to create a non-linear pipeline?

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What is the cleanest (simplest, most efficient, shortest, quickest, easiest, most elegant) way to create a non-linear pipeline like this in Bash?

I have three commands: mksock, irclogin, and ircpingpong. I want to pipe stdin, irclogin, and ircpingpong into mksock, and pipe mksock into stdout and ircpingpong. This means that mksock and ircpingpong are in a loop. I drew a diagram:

Diagram

irclogin only needs to be run once and be the first input into mksock. After that, ircpingpong, and stdin should be accepted at any time. I am currently using pipes and a temporary file like this:

#!/bin/bash

server=127.0.0.1
port=6667

infifo=/tmp/ircin
outfifo=/tmp/ircout
pongfifo=/tmp/ircpong

rm $infifo
rm $outfifo
rm $pongfifo
mkfifo $infifo
mkfifo $outfifo
touch $pongfifo

( irclogin | cat - $infifo & tail -f $pongfifo; ) | mksock $server $port | tee $outfifo | stdbuf -oL ircpingpong > $pongfifo &
cat < $outfifo &
cat > $infifo
pkill tail

This works, but I want to know if there is a better way to do this. It bothers me that I am using a file rather than a pipe for looping back from ircpingpong to mksock using tail. Using a pipe didn't work because, to my understanding, something is written to the pipe before tail -f starts reading from it, and so it misses it.

It also bothers me that I have to kill tail at the end of the script, because it doesn't stop on it's own and would leave the socket connected even after the script has ended.

pipelining shell unix bash
2 Answers

Here's something that uses just one fifo.

fifo=/tmp/myfifo
rm $fifo
mkfifo $fifo

((ircpingpong < $fifo &) && irclogin && cat) | mksock | tee $fifo

Add stdbuf as needed.

I don't know whether you will get your "something doesn't die on its own" problem; when I ctrl-c'ed the script, everything seemed to die.

user_25522900
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