download file using an ajax request

For those looking a more modern approach, you can use the fetch API. The following example shows how to download a spreadsheet file. It is easily done with the following code.

fetch(url, {
    body: JSON.stringify(data),
    method: 'POST',
    headers: {
        'Content-Type': 'application/json; charset=utf-8'
    },
})
.then(response => response.blob())
.then(response => {
    const blob = new Blob([response], {type: 'application/application/vnd.openxmlformats-officedocument.spreadsheetml.sheet'});
    const downloadUrl = URL.createObjectURL(blob);
    const a = document.createElement("a");
    a.href = downloadUrl;
    a.download = "file.xlsx";
    document.body.appendChild(a);
    a.click();
})

I believe this approach to be much easier to understand than other XMLHttpRequest solutions. Also, it has a similar syntax to the jQuery approach, without the need to add any additional libraries.

Of course, I would advise checking to which browser you are developing, since this new approach won't work on IE. You can find the full browser compatibility list on the following link.

Important: In this example I am sending a JSON request to a server listening on the given url. This url must be set, on my example I am assuming you know this part. Also, consider the headers needed for your request to work. Since I am sending a JSON, I must add the Content-Type header and set it to application/json; charset=utf-8, as to let the server know the type of request it will receive.

@Joao Marcos solution works for me but I had to modify the code to make it work on IE, below if what the code looks like

       downloadFile(url,filename) {
        var that = this;
        const extension =  url.split('/').pop().split('?')[0].split('.').pop();

        var req = new XMLHttpRequest();
        req.open("GET", url, true);
        req.responseType = "blob";
        req.onload = function (event) {
            const fileName = `${filename}.${extension}`;
            const blob = req.response;

            if (window.navigator.msSaveBlob) { // IE
                window.navigator.msSaveOrOpenBlob(blob, fileName);
            } 
            const link = document.createElement('a');
            link.href = window.URL.createObjectURL(blob);                
            link.download = fileName;
            link.click();
            URL.revokeObjectURL(link.href);

        };

        req.send();
    },

This solution is not very different from those above, but for me it works very well and i think it's clean.

I suggest to base64 encode the file server side (base64_encode(), if you are using PHP) and send the base64 encoded data to the client

On the client you do this:

 let blob = this.dataURItoBlob(THE_MIME_TYPE + "," + response.file);
 let uri = URL.createObjectURL(blob);
 let link = document.createElement("a");
 link.download = THE_FILE_NAME,
 link.href = uri;
 document.body.appendChild(link);
 link.click();
 document.body.removeChild(link);

This code puts the encoded data in a link and simulates a click on the link, then it removes it.

Your needs are covered by window.location('download.php');
But I think that you need to pass the file to be downloaded, not always download the same file, and that's why you are using a request, one option is to create a php file as simple as showfile.php and do a request like

var myfile = filetodownload.txt
var url = "shofile.php?file=" + myfile ;
ajaxRequest.open("GET", url, true);

showfile.php

<?php
$file = $_GET["file"] 
echo $file;

where file is the file name passed via Get or Post in the request and then catch the response in a function simply

if(ajaxRequest.readyState == 4){
                        var file = ajaxRequest.responseText;
                        window.location = 'downfile.php?file=' + file;  
                    }
                }

there is another solution to download a web page in ajax. But I am referring to a page that must first be processed and then downloaded.

First you need to separate the page processing from the results download.

1) Only the page calculations are made in the ajax call.

$.post("CalculusPage.php", { calculusFunction: true, ID: 29, data1: "a", data2: "b" },

       function(data, status) 
       {
            if (status == "success") 
            {
                /* 2) In the answer the page that uses the previous calculations is downloaded. For example, this can be a page that prints the results of a table calculated in the ajax call. */
                window.location.href = DownloadPage.php+"?ID="+29;
            }               
       }
);

// For example: in the CalculusPage.php

    if ( !empty($_POST["calculusFunction"]) ) 
    {
        $ID = $_POST["ID"];

        $query = "INSERT INTO ExamplePage (data1, data2) VALUES ('".$_POST["data1"]."', '".$_POST["data2"]."') WHERE id = ".$ID;
        ...
    }

// For example: in the DownloadPage.php

    $ID = $_GET["ID"];

    $sede = "SELECT * FROM ExamplePage WHERE id = ".$ID;
    ...

    $filename="Export_Data.xls";
    header("Content-Type: application/vnd.ms-excel");
    header("Content-Disposition: inline; filename=$filename");

    ...

I hope this solution can be useful for many, as it was for me.

this works for me

var dataObj = {
somekey:"someValue"
}
     $.ajax({
        method: "POST",
        url: "/someController/someMethod",
        data: dataObj,
        success: function (response) {
            const blob = new Blob([response], { type: 'text/csv' });
            const downloadUrl = URL.createObjectURL(blob);
            const a = document.createElement("a");
            a.href = downloadUrl;
            a.download = "file.csv";
            document.body.appendChild(a);
            a.click();
        }
    });