Is there any way in Android to force open a link to open in Chrome?

The different answers above are good but none is complete. This in all suited me the best which will :

try to open chrome web browser and in case exception occurs(chrome is not default or not installed), will ask for choosing the browser from user:

String uriString = "your uri string";

Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(uriString));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
intent.setPackage("com.android.chrome");
try {
    Log.d(TAG, "onClick: inTryBrowser");
    startActivity(intent);
} catch (ActivityNotFoundException ex) {
    Log.e(TAG, "onClick: in inCatchBrowser", ex );
    intent.setPackage(null);
    startActivity(Intent.createChooser(intent, "Select Browser"));
}

Here's a more generic approach - it first find outs the package name for the default browser, which handles "http://" URLs, then uses the approach mentioned in the other answers to explicitly open the URL in a browser:

    public void openUrlInBrowser(Context context, String url) {
        // Find out package name of default browser
        Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse("http://"));
        ResolveInfo resolveInfo = context.getPackageManager().resolveActivity(browserIntent, PackageManager.MATCH_DEFAULT_ONLY);
        String packageName = resolveInfo.activityInfo.packageName;

        // Use the explicit browser package name
        Intent i = new Intent(Intent.ACTION_VIEW);
        i.setData(Uri.parse(url));
        i.setPackage(packageName);
        context.startActivity(i);
    }

Android open a link in chrome using Java :

Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse("your url link"));
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
i.setPackage("com.android.chrome");
try {
    context.startActivity(i);
} catch (ActivityNotFoundException e) {
 Toast.makeText(context, "unable to open chrome", Toast.LENGTH_SHORT).show();
 i.setPackage(null);
 context.startActivity(i);
}

Android open a link in chrome using Kotlin :

val i = Intent(Intent.ACTION_VIEW, Uri.parse("https://stackoverflow.com/"))
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
i.setPackage("com.android.chrome")
try {
  context!!.startActivity(i)
} catch (e: ActivityNotFoundException) {
  Toast.makeText(context, "unable to open chrome", Toast.LENGTH_SHORT).show()
  i.setPackage(null)
  context!!.startActivity(i)
}

In google play there is a big variety of chrome browser apps with different features

So it's correct to check all of them

fun Context.openChrome(url: String, onError: (() -> Unit)? = null) {
    openBrowser("com.android.chrome", url) {
        openBrowser("com.android.beta", url) {
            openBrowser("com.android.dev", url) {
                openBrowser("com.android.canary", url) {
                    onError?.invoke() ?: openBrowser(null, url)
                }
            }
        }
    }
}

fun Context.openBrowser(packageName: String?, url: String, onError: (() -> Unit)? = null) {
    try {
        startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(url)).apply {
            setPackage(packageName)
            addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
        })
    } catch (e: ActivityNotFoundException) {
        onError?.invoke()
    }
}

The following worked for me, inspired from the documentation of CATEGORY_APP_BROWSER:

Uri uri = Uri.parse("https://www.wonderpush.com");
Intent intent = Intent.makeMainSelectorActivity(Intent.ACTION_MAIN, Intent.CATEGORY_APP_BROWSER);
intent.setData(uri);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try {
    context.startActivity(intent);
} catch (ActivityNotFoundException e) {
    Logging.loge("No activity for intent " + intent, e);
}