How can I extract all values from a dictionary in Python?

For Python 3, you need:

list_of_dict_values = list(dict_name.values())

For nested dicts, lists of dicts, and dicts of listed dicts, ... you can use

from typing import Iterable

def get_all_values(d):
    if isinstance(d, dict):
        for v in d.values():
            yield from get_all_values(v)
    elif isinstance(d, Iterable): # or list, set, ... only
        for v in d:
            yield from get_all_values(v)
    else:
        yield d 

An example:

d = {'a': 1, 'b': {'c': 2, 'd': [3, 4]}, 'e': [{'f': 5}, {'g': set([6, 7])}]}
list(get_all_values(d)) # returns [1, 2, 3, 4, 5, 6, 7]

PS: Yes, I love yield. ;-)

Code of python file containing dictionary

dict={"Car":"Lamborghini","Mobile":"iPhone"}
print(dict)

If you want to print only values (instead of key) then you can use :

dict={"Car":"Lamborghini","Mobile":"iPhone"}
for thevalue in dict.values():
    print(thevalue)

This will print only values instead of key from dictionary

Bonus : If there is a dictionary in which values are stored in list and if you want to print values only on new line , then you can use :

dict={"Car":["Lamborghini","BMW","Mercedes"],"Mobile":["Iphone","OnePlus","Samsung"]}
nd = [value[i] for value in dict.values()
         for i in range(2)]
print(*nd,sep="\n")

Reference - Narendra Dwivedi - Extract Only Values From Dictionary

I know this question been asked years ago but its quite relevant even today.

>>> d = {1:-0.3246, 2:-0.9185, 3:-3985}
>>> l = list(d.values())
>>> l
[-0.3246, -0.9185, -3985]

To see the keys:

for key in d.keys():
    print(key)

To get the values that each key is referencing:

for key in d.keys():
    print(d[key])

Add to a list:

for key in d.keys():
    mylist.append(d[key])

dictionary_name={key1:value1,key2:value2,key3:value3}
dictionary_name.values()

Normal Dict.values()

will return something like this

dict_values(['value1'])

dict_values(['value2'])

If you want only Values use

• Use this

list(Dict.values())[0] # Under the List