Find the item with maximum occurrences in a list

If you're using Python 3.8 or above, you can use either statistics.mode() to return the first mode encountered or statistics.multimode() to return all the modes.

>>> import statistics
>>> data = [1, 2, 2, 3, 3, 4] 
>>> statistics.mode(data)
2
>>> statistics.multimode(data)
[2, 3]

If the list is empty, statistics.mode() throws a statistics.StatisticsError and statistics.multimode() returns an empty list.

Note before Python 3.8, statistics.mode() (introduced in 3.4) would additionally throw a statistics.StatisticsError if there is not exactly one most common value.

A simple way without any libraries or sets

def mcount(l):
  n = []                  #To store count of each elements
  for x in l:
      count = 0
      for i in range(len(l)):
          if x == l[i]:
              count+=1
      n.append(count)
  a = max(n)              #largest in counts list
  for i in range(len(n)):
      if n[i] == a:
          return(l[i],a)  #element,frequency
  return                  #if something goes wrong

Simple and best code:

def max_occ(lst,x):
    count=0
    for i in lst:
        if (i==x):
            count=count+1
    return count

lst=[1, 2, 45, 55, 5, 4, 4, 4, 4, 4, 4, 5456, 56, 6, 7, 67]
x=max(lst,key=lst.count)
print(x,"occurs ",max_occ(lst,x),"times")

Output: 4 occurs 6 times

if you are using numpy in your solution for faster computation use this:

import numpy as np
x = np.array([2,5,77,77,77,77,77,77,77,9,0,3,3,3,3,3])
y = np.bincount(x,minlength = max(x))
y = np.argmax(y)   
print(y)  #outputs 77

My (simply) code (three months studying Python):

def more_frequent_item(lst):
    new_lst = []
    times = 0
    for item in lst:
        count_num = lst.count(item)
        new_lst.append(count_num)
        times = max(new_lst)
    key = max(lst, key=lst.count)
    print("In the list: ")
    print(lst)
    print("The most frequent item is " + str(key) + ". Appears " + str(times) + " times in this list.")


more_frequent_item([1, 2, 45, 55, 5, 4, 4, 4, 4, 4, 4, 5456, 56, 6, 7, 67])

The output will be:

In the list: 
[1, 2, 45, 55, 5, 4, 4, 4, 4, 4, 4, 5456, 56, 6, 7, 67]
The most frequent item is 4. Appears 6 times in this list.

may something like this:

testList = [1, 2, 3, 4, 2, 2, 1, 4, 4] print(max(set(testList), key = testList.count))