Is it possible to overload [] operator twice? To allow, something like this: function[3][3](like in a two dimensional array).
If it is possible, I would like to see some example code.
Is it possible to overload [] operator twice? To allow, something like this: function[3][3](like in a two dimensional array).
If it is possible, I would like to see some example code.
If, instead of saying a[x][y], you would like to say a[{x,y}], you can do like this:
struct Coordinate { int x, y; }
class Matrix {
int** data;
operator[](Coordinate c) {
return data[c.y][c.x];
}
}
vector< vector< T > > or T** is required only when you have rows of variable length and way too inefficient in terms of memory usage/allocations if you require rectangular array consider doing some math instead! see at() method:
template<typename T > class array2d {
protected:
std::vector< T > _dataStore;
size_t _sx;
public:
array2d(size_t sx, size_t sy = 1): _sx(sx), _dataStore(sx*sy) {}
T& at( size_t x, size_t y ) { return _dataStore[ x+y*sx]; }
const T& at( size_t x, size_t y ) const { return _dataStore[ x+y*sx]; }
const T& get( size_t x, size_t y ) const { return at(x,y); }
void set( size_t x, size_t y, const T& newValue ) { at(x,y) = newValue; }
};
The shortest and easiest solution:
class Matrix
{
public:
float m_matrix[4][4];
// for statements like matrix[0][0] = 1;
float* operator [] (int index)
{
return m_matrix[index];
}
// for statements like matrix[0][0] = otherMatrix[0][0];
const float* operator [] (int index) const
{
return m_matrix[index];
}
};