How to remove the querystring and get only the URL?

user_831783 0
Viewed 204144

I'm using PHP to build the URL of the current page. Sometimes, URLs in the form of

www.example.com/myurl.html?unwantedthngs

are requested. I want to remove the ? and everything that follows it (querystring), such that the resulting URL becomes:

www.example.com/myurl.html

My current code is this:

<?php
function curPageURL() {
    $pageURL = 'http';
    if ($_SERVER["HTTPS"] == "on") {
        $pageURL .= "s";
    }
    $pageURL .= "://";
    if ($_SERVER["SERVER_PORT"] != "80") {
        $pageURL .= $_SERVER["SERVER_NAME"] . ":" .
            $_SERVER["SERVER_PORT"] . $_SERVER["REQUEST_URI"];
    } else {
        $pageURL .= $_SERVER["SERVER_NAME"] . $_SERVER["REQUEST_URI"];
    }
    return $pageURL;
}
?>
query-string php
16 Answers

You can use the parse_url build in function like that:

$baseUrl = $_SERVER['SERVER_NAME'] . parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH);
user_66060900

could also use following as per the php manual comment 

$_SERVER['REDIRECT_URL']

Please note this is working only for certain PHP environment only and follow the bellow comment from that page for more information;

Purpose: The URL path name of the current PHP file, path-info is N/A and excluding URL query string. Includes leading slash.

Caveat: This is before URL rewrites (i.e. it's as per the original call URL).

Caveat: Not set on all PHP environments, and definitely only ones with URL rewrites.

Works on web mode: Yes

Works on CLI mode: No

user_12192000 
explode('?', $_SERVER['REQUEST_URI'])[0]
user_109379760

Assuming you still want to get the URL without the query args (if they are not set), just use a shorthand if statement to check with strpos:

$request_uri = strpos( $_SERVER['REQUEST_URI'], '?' ) !== false ? strtok( $_SERVER["REQUEST_URI"], '?' ) : $_SERVER['REQUEST_URI'];
user_3785060
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