I want to check device id for my iPhone simulator application. But not using codebase. I know the way how to do with codebase, using UIDevice instance.
Is there any way to find device id without using codebase?
8 Answers
As so often, there is a Xcode terminal tool for that (part of the Xcode tools) see xcrun manpage
xcrun simctl list | egrep '(Booted)'
lists only all booted (could be more than one) Simulators
(remove | egrep '(Booted)' to see them all).
UIID results like
iPhone 6 Plus (AAAABD40-9DE6-44B7-A4EA-B34ABCDEFCA6) (Booted)
you can then lookup a folder in ~/Library/Developer/CoreSimulator/Deviceson your Mac and find all the "belongings" of that particular Simulator
You can search for just the booted devices and get the iOS version (different from @TiBooX's answer which just shows the active devices). You also don't need to use grep, you can just use the built in functionality of xcrun:
$ xcrun simctl list 'devices' 'booted'
Which will print out something like:
== Devices ==
-- iOS 10.3 --
-- iOS 11.4 --
-- iOS 12.4 --
-- iOS 13.4 --
iPhone 11 Pro (A5DEEA78-1E82-472E-B7CC-FFD27741CDA2) (Booted)
-- tvOS 13.4 --
-- watchOS 6.2 --
I would recommend adding the following alias to your .bashrc or .zshrc:
# Get the active simulator with
alias active-sims="xcrun simctl list 'devices' 'booted'"
This way you can just run active-sims without remembering the entire line every time.
Xcode -> Window -> Devices and Simulators -> Select Device for which you want identifier (Inside details you can see identifier)
There is another way without using command line, inside this plist file ~/Library/Developer/CoreSimulator/Devices/device_set.plist, it lists down all the devices with UUID.
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