Python regular expression again - match url

user_591804 0
Viewed 81705

I have such regexp:

 re.compile(r"((https?):((//)|(\\\\))+[\w\d:#@%/;$()~_?\+-=\\\.&]*)", re.MULTILINE|re.UNICODE)

But that doesn't include hashbangs (#!). What I need to change, to get it working? I know I can add ! to group with #@% etc, but that will select something like 

Check this out: http://example.com/something/!!!

and I want to avoid that.

python regex
7 Answers

It could be very long but in practice mine works pretty good. Please try this one ((http|https)\:\/\/)?[a-zA-Z0-9\.\/\?\:@\-_=#]+\.([a-zA-Z]){2,6}([a-zA-Z0-9\.\&\/\?\:@\-_=#])*

It matches all of the example below 

http://wwww.stackoverflow.com
abc.com
http://test.test-75.1474.stackoverflow.com/
stackoverflow.com/
stackoverflow.com
rfordyce@broadviewnet.com
http://www.example.com/etcetc
www.example.com/etcetc
example.com/etcetc
user:pass@example.com/etcetc
(www.itmag.com)
example.com/etcetc?query=aasd
example.com/etcetc?query=aasd&dest=asds
http://stackoverflow.com/questions/6427530/regular-expression-pattern-to-
match-url-with
www/Christina.V.Scott@gmail.com
line.lundvoll.nilsen@telemed.no.
s.hossain@unsw.edu.au 
s.hossain@unsw.edu.au
user_24873090

Based on this link we can use the library validators

For example:

import validators

valid=validators.url('https://codespeedy.com/')
if valid==True:
    print("Url is valid")
else:
    print("Invalid url")
user_89616420

This is the most completed pattern I use:

URL_PATTERN = r'[A-Za-z0-9]+://[A-Za-z0-9%-_]+(/[A-Za-z0-9%-_])*(#|\\?)[A-Za-z0-9%-_&=]*'
user_95019280

i use this to search for all http and https URLs, works like a charm URL_PATTERN= "http[s]*\S+"

user_196862340
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