How can I convert a string like 123,456.908 to float 123456.908 in Python?
How can I convert a string like 123,456.908 to float 123456.908 in Python?
If you don't know the locale and you want to parse any kind of number, use this parseNumber(text) function. It is not perfect but take into account most cases :
>>> parseNumber("a 125,00 €")
125
>>> parseNumber("100.000,000")
100000
>>> parseNumber("100 000,000")
100000
>>> parseNumber("100,000,000")
100000000
>>> parseNumber("100 000 000")
100000000
>>> parseNumber("100.001 001")
100.001
>>> parseNumber("$.3")
0.3
>>> parseNumber(".003")
0.003
>>> parseNumber(".003 55")
0.003
>>> parseNumber("3 005")
3005
>>> parseNumber("1.190,00 €")
1190
>>> parseNumber("1190,00 €")
1190
>>> parseNumber("1,190.00 €")
1190
>>> parseNumber("$1190.00")
1190
>>> parseNumber("$1 190.99")
1190.99
>>> parseNumber("1 000 000.3")
1000000.3
>>> parseNumber("1 0002,1.2")
10002.1
>>> parseNumber("")
>>> parseNumber(None)
>>> parseNumber(1)
1
>>> parseNumber(1.1)
1.1
>>> parseNumber("rrr1,.2o")
1
>>> parseNumber("rrr ,.o")
>>> parseNumber("rrr1rrr")
1
If you have a comma as decimals separator and the dot as thousands separator, you can do:
s = s.replace('.','').replace(',','.')
number = float(s)
Hope it will help
Better solution for different currency formats:
def text_currency_to_float(text):
t = text
dot_pos = t.rfind('.')
comma_pos = t.rfind(',')
if comma_pos > dot_pos:
t = t.replace(".", "")
t = t.replace(",", ".")
else:
t = t.replace(",", "")
return(float(t))
Just replace, with replace().
f = float("123,456.908".replace(',','')) print(type(f))
type() will show you that it has converted into a float