What's the correct way to convert bytes to a hex string in Python 3?

New in python 3.8, you can pass a delimiter argument to the hex function, as in this example

>>> value = b'\xf0\xf1\xf2'
>>> value.hex('-')
'f0-f1-f2'
>>> value.hex('_', 2)
'f0_f1f2'
>>> b'UUDDLRLRAB'.hex(' ', -4)
'55554444 4c524c52 4142'

https://docs.python.org/3/library/stdtypes.html#bytes.hex

it can been used the format specifier %x02 that format and output a hex value. For example:

>>> foo = b"tC\xfc}\x05i\x8d\x86\x05\xa5\xb4\xd3]Vd\x9cZ\x92~'6"
>>> res = ""
>>> for b in foo:
...     res += "%02x" % b
... 
>>> print(res)
7443fc7d05698d8605a5b4d35d56649c5a927e2736

OK, the following answer is slightly beyond-scope if you only care about Python 3, but this question is the first Google hit even if you don't specify the Python version, so here's a way that works on both Python 2 and Python 3.

I'm also interpreting the question to be about converting bytes to the str type: that is, bytes-y on Python 2, and Unicode-y on Python 3.

Given that, the best approach I know is:

import six

bytes_to_hex_str = lambda b: ' '.join('%02x' % i for i in six.iterbytes(b))

The following assertion will be true for either Python 2 or Python 3, assuming you haven't activated the unicode_literals future in Python 2:

assert bytes_to_hex_str(b'jkl') == '6a 6b 6c'

(Or you can use ''.join() to omit the space between the bytes, etc.)