Passing named parameters to a php function through call_user_func_array

user_757472 0
Viewed 26101

When trying to call a function in a child class with an arbitrary set of parameters, I'm having the following problem:

class Base{

    function callDerived($method,$params){
        call_user_func_array(array($this,$method),$params);
    }
}

class Derived extends Base{
    function test($foo,$bar){
        print "foo=$foo, bar=$bar\n";
    }
}

$d = new Derived();
$d->callDerived('test',array('bar'=>'2','foo'=>1));

Outputs:

foo=2, bar=1

Which... is not exactly what I wanted - is there a way to achieve this beyond re-composing the array with the index order of func_get_args? And yes, of course, I could simply pass the whole array and deal with it in the function... but that's not what I want to do.

Thanks

function php
8 Answers

UPDATE: PHP 8 Now supports named parameters. And it works with call_user_func_array if you pass an associative array. So you can simply do this:

<?php

function myFunc($foo, $bar) {
    echo "foo=$foo, bar=$bar\n";
}

call_user_func_array('myFunc', ['bar' => 2, 'foo' => 1]);
// Outputs:  foo=1, bar=2

In your code, you'll be happy to know that you don't have to change a thing. Just upgrade to PHP 8 and it'll work as you expected

user_9322510
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