Convert date formats in bash

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I have a date in this format: "27 JUN 2011" and I want to convert it to 20110627

Is it possible to do in bash?

7 Answers

If you would like a bash function that works both on Mac OS X and Linux:

#
# Convert one date format to another
# 
# Usage: convert_date_format <input_format> <date> <output_format>
#
# Example: convert_date_format '%b %d %T %Y %Z' 'Dec 10 17:30:05 2017 GMT' '%Y-%m-%d'
convert_date_format() {
  local INPUT_FORMAT="$1"
  local INPUT_DATE="$2"
  local OUTPUT_FORMAT="$3"
  local UNAME=$(uname)

  if [[ "$UNAME" == "Darwin" ]]; then
    # Mac OS X
    date -j -f "$INPUT_FORMAT" "$INPUT_DATE" +"$OUTPUT_FORMAT"
  elif [[ "$UNAME" == "Linux" ]]; then
    # Linux
    date -d "$INPUT_DATE" +"$OUTPUT_FORMAT"
  else
    # Unsupported system
    echo "Unsupported system"
  fi
}

# Example: 'Dec 10 17:30:05 2017 GMT' => '2017-12-10'
convert_date_format '%b %d %T %Y %Z' 'Dec 10 17:30:05 2017 GMT' '%Y-%m-%d'

It's enough to do:

data=`date`
datatime=`date -d "${data}" '+%Y%m%d'`
echo $datatime
20190206

If you want to add also the time you can use in that way

data=`date`
datatime=`date -d "${data}" '+%Y%m%d %T'`

echo $data
Wed Feb 6 03:57:15 EST 2019

echo $datatime
20190206 03:57:15
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