How do I get the picture size with PIL?

Since scipy's imread is deprecated, use imageio.imread.

1. Install - pip install imageio
2. Use height, width, channels = imageio.imread(filepath).shape

This is a complete example loading image from URL, creating with PIL, printing the size and resizing...

import requests
h = { 'User-Agent': 'Neo'}
r = requests.get("https://images.freeimages.com/images/large-previews/85c/football-1442407.jpg", headers=h)

from PIL import Image
from io import BytesIO
# create image from binary content
i = Image.open(BytesIO(r.content))


width, height = i.size
print(width, height)
i = i.resize((100,100))
display(i)

Note that PIL will not apply the EXIF rotation information (at least up to v7.1.1; used in many jpgs). A quick fix to accomodate this:

def get_image_dims(file_path):
    from PIL import Image as pilim
    im = pilim.open(file_path)
    # returns (w,h) after rotation-correction
    return im.size if im._getexif().get(274,0) < 5 else im.size[::-1]

Here's how you get the image size from the given URL in Python 3:

from PIL import Image
import urllib.request
from io import BytesIO

file = BytesIO(urllib.request.urlopen('http://getwallpapers.com/wallpaper/full/b/8/d/32803.jpg').read())
im = Image.open(file)
width, height = im.size

Followings gives dimensions as well as channels:

import numpy as np
from PIL import Image

with Image.open(filepath) as img:
    shape = np.array(img).shape