Formatting a float to 2 decimal places

user_779616 0
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I am currently building a sales module for a clients website. So far I have got the sale price to calculate perfectly but where I have come stuck is formatting the output to 2 decimal places.

I am currently calling this in a variable so that I can data bind the results to a listview.

Sale = float.Parse(((x.Sale_Price - (x.Sale_Price * (x.Discount_Price / 100))).ToString())),

Can anyone show me how to format the output to 2 decimal places?? Many Thanks!

decimal floating-point variables c#
9 Answers

This is for cases that you want to use interpolated strings. I'm actually posting this because I'm tired of trial and error and eventually scrolling through tons of docs every time I need to format some scalar.

$"{1234.5678:0.00}"        "1234.57"        2 decimal places, notice that value is rounded
$"{1234.5678,10:0.00}"     "   1234.57"     right-aligned
$"{1234.5678,-10:0.00}"    "1234.57   "     left-aligned
$"{1234.5678:0.#####}"     "1234.5678"      5 optional digits after the decimal point
$"{1234.5678:0.00000}"     "1234.56780"     5 forced digits AFTER the decimal point, notice the trailing zero
$"{1234.5678:00000.00}"    "01234.57"       5 forced digits BEFORE the decimal point, notice the leading zero
$"{1234.5612:0}"           "1235"           as integer, notice that value is rounded
$"{1234.5678:F2}"          "1234.57"        standard fixed-point
$"{1234.5678:F5}"          "1234.56780"     5 digits after the decimal point, notice the trailing zero
$"{1234.5678:g2}"          "1.2e+03"        standard general with 2 meaningful digits, notice "e"
$"{1234.5678:G2}"          "1.2E+03"        standard general with 2 meaningful digits, notice "E"
$"{1234.5678:G3}"          "1.23E+03"       standard general with 3 meaningful digits
$"{1234.5678:G5}"          "1234.6"         standard general with 5 meaningful digits
$"{1234.5678:e2}"          "1.23e+003"      standard exponential with 2 digits after the decimal point, notice "e"
$"{1234.5678:E3}"          "1.235E+003"     standard exponential with 3 digits after the decimal point, notice "E"
$"{1234.5678:N2}"          "1,234.57"       standard numeric, notice the comma
$"{1234.5678:C2}"          "$1,234.57"      standard currency, notice the dollar sign
$"{1234.5678:P2}"          "123,456.78 %"   standard percent, notice that value is multiplied by 100
$"{1234.5678:2}"           "2"              :)

Performance Warning

Interpolated strings are slow. In my experience this is the order (fast to slow):

  1. value.ToString(format)+" blah blah"
  2. string.Format("{0:format} blah blah", value)
  3. $"{value:format} blah blah"
user_20930770

As already mentioned, you will need to use a formatted result; which is all done through the Write(), WriteLine(), Format(), and ToString() methods.

What has not been mentioned is the Fixed-point Format which allows for a specified number of decimal places. It uses an 'F' and the number following the 'F' is the number of decimal places outputted, as shown in the examples.

Console.WriteLine("{0:F2}", 12);    // 12.00 - two decimal places
Console.WriteLine("{0:F0}", 12.3);  // 12 - ommiting fractions
user_98561120

I like to use

$"{value:0.##}

It displays two decimals only if there is some value at those places.

Examples:

$"{50.255:0.##} //50,25
$"{50.2:0.##}   //50,2
$"{50.00:0.##}  //50
user_54775060 
    private float LimitDecimalPlace(double number,int limitPlace)
    {
        float result = 0;
        string sNumber = number.ToString();
        int decimalIndex = sNumber.IndexOf(".");
        if (decimalIndex != -1)
        {
            sNumber = sNumber.Remove(decimalIndex + limitPlace + 1);
        }
       
        result = float.Parse(sNumber);
        return result;
    }
user_195940420
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