Array to Hash Ruby

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Convert this Array:

a = ["item 1", "item 2", "item 3", "item 4"] 

...to a Hash:

{ "item 1" => "item 2", "item 3" => "item 4" }

i.e. elements at even indexes are keys and odd ones are values.

9 Answers

All answers assume the starting array is unique. OP did not specify how to handle arrays with duplicate entries, which result in duplicate keys.

Let's look at:

a = ["item 1", "item 2", "item 3", "item 4", "item 1", "item 5"]

You will lose the item 1 => item 2 pair as it is overridden bij item 1 => item 5:

Hash[*a]
=> {"item 1"=>"item 5", "item 3"=>"item 4"}

All of the methods, including the reduce(&:merge!) result in the same removal.

It could be that this is exactly what you expect, though. But in other cases, you probably want to get a result with an Array for value instead:

{"item 1"=>["item 2", "item 5"], "item 3"=>["item 4"]}

The naïve way would be to create a helper variable, a hash that has a default value, and then fill that in a loop:

result = Hash.new {|hash, k| hash[k] = [] } # Hash.new with block defines unique defaults.
a.each_slice(2) {|k,v| result[k] << v }
a
=> {"item 1"=>["item 2", "item 5"], "item 3"=>["item 4"]}

It might be possible to use assoc and reduce to do above in one line, but that becomes much harder to reason about and read.

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