PHP: Check if variable exist but also if has a value equal to something

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I have (or not) a variable $_GET['myvar'] coming from my query string and I want to check if this variable exists and also if the value corresponds to something inside my if statement:

What I'm doing and think is not the best way to do:

if(isset($_GET['myvar']) && $_GET['myvar'] == 'something'): do something

My question is, exist any way to do this without declare the variable twice?

That is a simple case but imagine have to compare many of this $myvar variables.

isset if-statement variables php
13 Answers

As of PHP7 you can use the Null Coalescing Operator ?? to avoid the double reference:

// $_GET['myvar'] isn't set...
echo ($_GET['myvar'] ?? '') == 'hello' ? "hello!\n" : "goodbye!\n";

// $_GET['myvar'] is set but != 'hello'
$_GET['myvar'] = 'farewell';
echo ($_GET['myvar'] ?? '') == 'hello' ? "hello!\n" : "goodbye!\n";

// $_GET['myvar'] is set and == 'hello'
$_GET['myvar'] = 'hello';
echo ($_GET['myvar'] ?? '') == 'hello' ? "hello!\n" : "goodbye!\n";

Output:

goodbye!
goodbye!
hello!

Code demo on 3v4l.org

In general, the expression

$a ?? $b

is equivalent to

isset($a) ? $a : $b

Note that in the code example it is necessary to place parentheses around $_GET['myvar'] ?? '' as == has higher precedence than ?? and thus

$_GET['myvar'] ?? '' == 'hello'

would evaluate to:

$_GET['myvar'] ?? ('' == 'hello')

which would be true as long as $_GET['myvar'] was set and "truthy" (see the manual) and false otherwise (since '' == 'hello' is false).

Precedence code demo on 3v4l.org

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