python: get the print output in an exec statement

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I want to get the output of an exec(...) Here is my code:

code = """
i = [0,1,2]
for j in i :
    print j
"""
result = exec(code)

How could I get the things that print outputed? How can I get something like:

0
1
2

Regards and thanks.

7 Answers

Here is a small correction of Frédéric's answer. We need to handle a possible exception in exec() to return back normal stdout. Otherwise we could not see farther print outputs:

code = """
i = [0,1,2]
for j in i :
print j
"""

from cStringIO import StringIO
old_stdout = sys.stdout
redirected_output = sys.stdout = StringIO()
try:
    exec(code)
except:
    raise 
finally: # !
    sys.stdout = old_stdout # !

print redirected_output.getvalue()
...
print 'Hello, World!' # now we see it in case of the exception above

Python 3: Get the output of the exec into a variable

import io, sys
print(sys.version)

#keep a named handle on the prior stdout 
old_stdout = sys.stdout 
#keep a named handle on io.StringIO() buffer 
new_stdout = io.StringIO() 
#Redirect python stdout into the builtin io.StringIO() buffer 
sys.stdout = new_stdout 

#variable contains python code referencing external memory
mycode = """print( local_variable + 5 )""" 

local_variable = 2
exec(mycode)

#stdout from mycode is read into a variable
result = sys.stdout.getvalue().strip()

#put stdout back to normal 
sys.stdout = old_stdout 
 
print("result of mycode is: '" + str(result) + "'") 

Prints:

3.4.8
result of mycode is: '7'

Also a reminder that python exec(...) is evil and bad because 1. It makes your code into unreadable goto-spaghetti. 2. Introduces end-user code injection opportunities, and 3. Throws the exception stacktrace into chaos because exec is made of threads and threads are bad mmkay.

You could combine exec with eval to get an output as list:

ExecString('i = [0,1,2]');
println(EvalStr('[j for j in i]'));
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