I have this number:
$double = '21.188624';
After using number_format($double, 2, ',', ' ') I get:
21,19
But what I want is:
21,18
Any ideea how can I make this work?
Thank you.
I have this number:
$double = '21.188624';
After using number_format($double, 2, ',', ' ') I get:
21,19
But what I want is:
21,18
Any ideea how can I make this work?
Thank you.
I know that this an old question, but it still actual :) .
How about this function?
function numberFormatPrecision($number, $precision = 2, $separator = '.')
{
$numberParts = explode($separator, $number);
$response = $numberParts[0];
if (count($numberParts)>1 && $precision > 0) {
$response .= $separator;
$response .= substr($numberParts[1], 0, $precision);
}
return $response;
}
Usage:
// numbers test
numberFormatPrecision(19, 2, '.'); // expected 19 return 19
numberFormatPrecision(19.1, 2, '.'); //expected 19.1 return 19.1
numberFormatPrecision(19.123456, 2, '.'); //expected 19.12 return 19.12
numberFormatPrecision(19.123456, 0, '.'); //expected 19 return 19
// negative numbers test
numberFormatPrecision(-19, 2, '.'); // expected -19 return -19
numberFormatPrecision(-19.1, 2, '.'); //expected -19.1 return -19.1
numberFormatPrecision(-19.123456, 2, '.'); //expected -19.12 return -19.12
numberFormatPrecision(-19.123456, 0, '.'); //expected -19 return -19
// precision test
numberFormatPrecision(-19.123456, 4, '.'); //expected -19.1234 return -19.1234
// separator test
numberFormatPrecision('-19,123456', 3, ','); //expected -19,123 return -19,123 -- comma separator
Function (only precision):
function numberPrecision($number, $decimals = 0)
{
$negation = ($number < 0) ? (-1) : 1;
$coefficient = 10 ** $decimals;
return $negation * floor((string)(abs($number) * $coefficient)) / $coefficient;
}
Examples:
numberPrecision(2557.9999, 2); // returns 2557.99
numberPrecision(2557.9999, 10); // returns 2557.9999
numberPrecision(2557.9999, 0); // returns 2557
numberPrecision(2557.9999, -2); // returns 2500
numberPrecision(2557.9999, -10); // returns 0
numberPrecision(-2557.9999, 2); // returns -2557.99
numberPrecision(-2557.9999, 10); // returns -2557.9999
numberPrecision(-2557.9999, 0); // returns -2557
numberPrecision(-2557.9999, -2); // returns -2500
numberPrecision(-2557.9999, -10); // returns 0
Function (full functionality):
function numberFormat($number, $decimals = 0, $decPoint = '.' , $thousandsSep = ',')
{
$negation = ($number < 0) ? (-1) : 1;
$coefficient = 10 ** $decimals;
$number = $negation * floor((string)(abs($number) * $coefficient)) / $coefficient;
return number_format($number, $decimals, $decPoint, $thousandsSep);
}
Examples:
numberFormat(2557.9999, 2, ',', ' '); // returns 2 557,99
numberFormat(2557.9999, 10, ',', ' '); // returns 2 557,9999000000
numberFormat(2557.9999, 0, ',', ' '); // returns 2 557
numberFormat(2557.9999, -2, ',', ' '); // returns 2 500
numberFormat(2557.9999, -10, ',', ' '); // returns 0
numberFormat(-2557.9999, 2, ',', ' '); // returns -2 557,99
numberFormat(-2557.9999, 10, ',', ' '); // returns -2 557,9999000000
numberFormat(-2557.9999, 0, ',', ' '); // returns -2 557
numberFormat(-2557.9999, -2, ',', ' '); // returns -2 500
numberFormat(-2557.9999, -10, ',', ' '); // returns 0
$double = '21.188624';
$teX = explode('.', $double);
if(isset($teX[1])){
$de = substr($teX[1], 0, 2);
$final = $teX[0].'.'.$de;
$final = (float) $final;
}else{
$final = $double;
}
final will be 21.18
In case you need 2 fixed decimal places, you can try this!
@Dima's solution is working for me, but it prints "19.90" as "19.9" so I made some changes as follows:
<?php
function numberPrecision($number, $decimals = 0)
{
$negation = ($number < 0) ? (-1) : 1;
$coefficient = 10 ** $decimals;
$result = $negation * floor((string)(abs($number) * $coefficient)) / $coefficient;
$arr = explode(".", $result);
$num = $arr[0];
if(empty($arr[1]))
$num .= ".00";
else if(strlen($arr[1]) == 1)
$num .= "." . $arr[1] . "0";
else
$num .= ".". $arr[1];
return $num;
}
echo numberPrecision(19.90,2); // 19.90
So, what I did is, I just break the result into two parts with explode function. and convert the result into a string with concatenation!
The faster way as exploding(building arrays) is to do it with string commands like this:
$number = ABC.EDFG;
$precision = substr($number, strpos($number, '.'), 3); // 3 because . plus 2 precision
$new_number = substr($number, 0, strpos($number, '.')).$precision;
The result ist ABC.ED in this case because of 2 precision If you want more precision just change the 3 to 4 or X to have X-1 precision
Cheers
Javascript Version
function numberFormat($number, $decimals = 0, $decPoint = '.' , $thousandsSep = ',')
{
return number_format((Math.floor($number * 100) / 100).toFixed($decimals), $decimals, $decPoint, $thousandsSep );
}
// https://locutus.io/php/strings/number_format/
function number_format(number, decimals, decPoint, thousandsSep) {
if(decimals === 'undefined') decimals = 2;
number = (number + '').replace(/[^0-9+\-Ee.]/g, '')
const n = !isFinite(+number) ? 0 : +number
const prec = !isFinite(+decimals) ? 0 : Math.abs(decimals)
const sep = (typeof thousandsSep === 'undefined') ? ',' : thousandsSep
const dec = (typeof decPoint === 'undefined') ? '.' : decPoint
let s = ''
const toFixedFix = function (n, prec) {
if (('' + n).indexOf('e') === -1) {
return +(Math.round(n + 'e+' + prec) + 'e-' + prec)
} else {
const arr = ('' + n).split('e')
let sig = ''
if (+arr[1] + prec > 0) {
sig = '+'
}
return (+(Math.round(+arr[0] + 'e' + sig + (+arr[1] + prec)) + 'e-' + prec)).toFixed(prec)
}
}
// @todo: for IE parseFloat(0.55).toFixed(0) = 0;
s = (prec ? toFixedFix(n, prec).toString() : '' + Math.round(n)).split('.')
if (s[0].length > 3) {
s[0] = s[0].replace(/\B(?=(?:\d{3})+(?!\d))/g, sep)
}
if ((s[1] || '').length < prec) {
s[1] = s[1] || ''
s[1] += new Array(prec - s[1].length + 1).join('0')
}
return s.join(dec)
}