How to represent multiple conditions in a shell if statement?

user_389955 0
Viewed 1055932

I want to represent multiple conditions like this:

if [ ( $g -eq 1 -a "$c" = "123" ) -o ( $g -eq 2 -a "$c" = "456" ) ]   
then  
    echo abc;  
else  
    echo efg;   
fi

but when I execute the script, it shows

syntax error at line 15: `[' unexpected,

where line 15 is the one showing if ....

What is wrong with this condition? I guess something is wrong with the ().

shell unix bash
8 Answers

Be careful if you have spaces in your string variables and you check for existence. Be sure to quote them properly.

if [ ! "${somepath}" ] || [ ! "${otherstring}" ] || [ ! "${barstring}" ] ; then
user_13292140

In Bash, you can use the following technique for string comparison

if [ $var OP "val" ]; then
    echo "statements"
fi

Example:

var="something"
if [ $var != "otherthing" ] && [ $var != "everything" ] && [ $var != "allthings" ]; then
    echo "this will be printed"
else
    echo "this will not be printed"
fi
user_52732030

You can also chain more than two conditions:

if [ \( "$1" = '--usage' \) -o \( "$1" = '' \) -o \( "$1" = '--help' \) ]
then
   printf "\033[2J";printf "\033[0;0H"
   cat << EOF_PRINT_USAGE

   $0 - Purpose: upsert qto http json data to postgres db

   USAGE EXAMPLE:

   $0 -a foo -a bar



EOF_PRINT_USAGE
   exit 1
fi
YordanGeorgiev_657060
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