I can check whether a number is odd/even using bitwise operators. Can I check whether a number is positive/zero/negative without using any conditional statements/operators like if/ternary etc.
Can the same be done using bitwise operators and some trick in C or in C++?
#include<stdio.h>
int checksign(int n)
{
return (n >= 0 && (n & (1<<32-1)) >=0);
}
void main()
{
int num = 11;
if(checksign(num))
{
printf("Unsigned number");
}
else
{
printf("signed Number");
}
}
Without if:
string pole[2] = {"+", "-"};
long long x;
while (true){
cin >> x;
cout << pole[x/-((x*(-1))-1)] << "\n\n";
}
(not working for 0)
if(n & (1<<31))
{
printf("Negative number");
}
else{
printf("positive number");
}
It check the first bit which is most significant bit of the n number and then & operation is work on it if the value is 1 which is true then the number is negative and it not then it is positive number