Using Spring 3 autowire in a standalone Java application

user_441549 0
Viewed 102717

Here is my code:

public class Main {

    public static void main(String[] args) {
        Main p = new Main();
        p.start(args);
    }

    @Autowired
    private MyBean myBean;
    private void start(String[] args) {
        ApplicationContext context = 
            new ClassPathXmlApplicationContext("META-INF/config.xml");
        System.out.println("my beans method: " + myBean.getStr());
    }
}

@Service 
public class MyBean {
    public String getStr() {
        return "string";
    }
}

<beans xmlns="http://www.springframework.org/schema/beans"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xmlns:context="http://www.springframework.org/schema/context"
 xsi:schemaLocation="http://www.springframework.org/schema/beans
     http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
     http://www.springframework.org/schema/context
     http://www.springframework.org/schema/context/spring-context-3.0.xsd"> 
    <context:annotation-config /> 
    <context:component-scan base-package="mypackage"/>
</beans>

Why doesn't this work? I get NullPointerException. Is it possible to use autowiring in a standalone application?

autowired program-entry-point dependency-injection spring java
5 Answers

I case you are running SpringBoot:

I just had the same problem, that I could not Autowire one of my services from the static main method.

See below an approach in case you are relying on SpringApplication.run:

@SpringBootApplication
public class PricingOnlineApplication {

    @Autowired
    OrchestratorService orchestratorService;

    public static void main(String[] args) {
        ConfigurableApplicationContext context = SpringApplication.run(PricingOnlineApplication.class, args);
        PricingOnlineApplication application = context.getBean(PricingOnlineApplication.class);

        application.start();
    }

    private void start() {
        orchestratorService.performPricingRequest(null);
    }

}

I noticed that SpringApplication.run returns a context which can be used similar to the above described approaches. From there, it is exactly the same as above ;-)

user_131464150

A nice solution would be to do following,

import org.springframework.beans.BeansException;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;
import org.springframework.stereotype.Component;

@Component
public class SpringContext implements ApplicationContextAware {

private static ApplicationContext context;

/**
 * Returns the Spring managed bean instance of the given class type if it exists.
 * Returns null otherwise.
 * @param beanClass
 * @return
 */
public static <T extends Object> T getBean(Class<T> beanClass) {
    return context.getBean(beanClass);
}

@Override
public void setApplicationContext(ApplicationContext context) throws BeansException {

    // store ApplicationContext reference to access required beans later on
    SpringContext.context = context;
}
}

Then you can use it like:

YourClass yourClass = SpringContext.getBean(YourClass.class);

I found this very nice solution in the following website: https://confluence.jaytaala.com/pages/viewpage.action?pageId=18579463

user_56342880
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