How can I get the class name from a C++ object?

user_113124 0
Viewed 236472

Is it possible to get the object name too?

#include<cstdio>

class one {
public:
    int no_of_students;
    one() { no_of_students = 0; }
    void new_admission() { no_of_students++; }
};

int main() {
    one A;
    for(int i = 0; i < 99; i++) {
        A.new_admission();
    }
    cout<<"class"<<[classname]<<" "<<[objectname]<<"has "
        <<A.no_of_students<<" students";
}

where I can fetch the names, something like 

[classname] = A.classname() = one
[objectname] = A.objectname() = A

Does C++ provide any mechanism to achieve this?

class c++
8 Answers

Just write simple template:

template<typename T>
const char* getClassName(T) {
  return typeid(T).name();
}

struct A {} a;

void main() {
   std::cout << getClassName(a);
}
user_30208250

You can try this:

template<typename T>
inline const char* getTypeName() {
  return typeid(T).name();
}

#define DEFINE_TYPE_NAME(type, type_name)  \
  template<>                               \
  inline const char* getTypeName<type>() { \
    return type_name;                      \
  }

DEFINE_TYPE_NAME(int, "int")
DEFINE_TYPE_NAME(float, "float")
DEFINE_TYPE_NAME(double, "double")
DEFINE_TYPE_NAME(std::string, "string")
DEFINE_TYPE_NAME(bool, "bool")
DEFINE_TYPE_NAME(uint32_t, "uint")
DEFINE_TYPE_NAME(uint64_t, "uint")
// add your custom types' definitions

And call it like that:

void main() {
 std::cout << getTypeName<int>();
}
user_29206980
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