In c# I am converting a byte to binary, the actual answer is 00111111 but the result being given is 111111. Now I really need to display even the 2 0s in front. Can anyone tell me how to do this?
I am using:
Convert.ToString(byteArray[20],2)
and the byte value is 63
If I understand correctly, you have 20 values that you want to convert, so it's just a simple change of what you wrote.
To change single byte to 8 char string: Convert.ToString( x, 2 ).PadLeft( 8, '0' )
To change full array:
byte[] a = new byte[] { 1, 10, 100, 255, 200, 20, 2 };
string[] b = a.Select( x => Convert.ToString( x, 2 ).PadLeft( 8, '0' ) ).ToArray();
// Returns array:
// 00000010
// 00010100
// 11001000
// 11111111
// 01100100
// 00001010
// 00000001
To change your byte array to single string, with bytes separated with space:
byte[] a = new byte[] { 1, 10, 100, 255, 200, 20, 2 };
string s = string.Join( " ",
a.Select( x => Convert.ToString( x, 2 ).PadLeft( 8, '0' ) ) );
// Returns: 00000001 00001010 01100100 11111111 11001000 00010100 00000010
if ordering of bytes is incorrect use IEnumerable.Reverse():
byte[] a = new byte[] { 1, 10, 100, 255, 200, 20, 2 };
string s = string.Join( " ",
a.Reverse().Select( x => Convert.ToString( x, 2 ).PadLeft( 8, '0' ) ) );
// Returns: 00000010 00010100 11001000 11111111 01100100 00001010 00000001