Find the indexes of all regex matches?

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I'm parsing strings that could have any number of quoted strings inside them (I'm parsing code, and trying to avoid PLY). I want to find out if a substring is quoted, and I have the substrings index. My initial thought was to use re to find all the matches and then figure out the range of indexes they represent.

It seems like I should use re with a regex like \"[^\"]+\"|'[^']+' (I'm avoiding dealing with triple quoted and such strings at the moment). When I use findall() I get a list of the matching strings, which is somewhat nice, but I need indexes.

My substring might be as simple as c, and I need to figure out if this particular c is actually quoted or not.

3 Answers

#To get indice of all occurence

S = input() # Source String 
k = input() # String to be searched
import re
pattern = re.compile(k)
r = pattern.search(S)
if not r: print("(-1, -1)")
while r:
    print("({0}, {1})".format(r.start(), r.end() - 1))
    r = pattern.search(S,r.start() + 1)

This should solve your issue pattern=r"(?=(\"[^\"]+\"|'[^']+'))"

Then use the following to get all overlapping indices,

indicesTuple=[(mObj.start(1),mObj.end(1)-1) for mObj in re.finditer(pattern,input)]

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