How to check if today is a weekend in bash?

printf also has date

printf -v day '%(%a)T'
case $day in 
    Sat|Sun) echo "Hooray!";;
esac

https://ideone.com/wU7C0c - demo

I am not really sure if this is suited to this question but I wanted to share this it to help others out and this is the closest Stack question to what I was looking for.

This is a shell script that I use for starting an application when i boot my computer, the application cannot connect to its server over the weekend (its down for maintenance as the service doesn't run at weekends (forex trading application).

Information about this script, d is 1 to 7 (mon to sun) h is 24 time. You can adjust this to your own settings, maybe you have a midweek maintenance or any other cause. This is my first ever shell script, so I'm sure there is a better way and if anybody wants make edits, feel free I will review for acceptance (or somebody else may do it)

#!/bin/bash
d=$(date +%u)
h=$(date +%H)
case $d in
    '5')
    # Friday after 10pm
    if (($h >= 22)) ; then  
        exit
    fi
    ;;
    '6')
    # all day saturday
        exit
    ;;
    '7')
    #sunday before 10pm
    if (($h < 22)) ; then  
        exit
    fi
    ;;
    *)
    # any other time run the program

    ;;
esac

I like this way of running programs on weekdays:

[[ $(date +%u) -lt 6 ]] && weekday-program

It is a bit tricky construction, but compact and easy to add.