Generating an MD5 checksum of a file

user_408168 0
Viewed 418262

Is there any simple way of generating (and checking) MD5 checksums of a list of files in Python? (I have a small program I'm working on, and I'd like to confirm the checksums of the files).

hashlib checksum md5 python
7 Answers

In Python 3.8+, you can can use the assignment operator := (along with hashlib) like this:

import hashlib
with open("your_filename.txt", "rb") as f:
    file_hash = hashlib.md5()
    while chunk := f.read(8192):
        file_hash.update(chunk)

print(file_hash.digest())
print(file_hash.hexdigest())  # to get a printable str instead of bytes

Consider using hashlib.blake2b instead of md5 (just replace md5 with blake2b in the above snippet). It's cryptographically secure and faster than MD5.

user_30645380 
hashlib.md5(pathlib.Path('path/to/file').read_bytes()).hexdigest()
user_37989640

You could use simple-file-checksum1, which just uses subprocess to call openssl for macOS/Linux and CertUtil for Windows and extracts only the digest from the output:

Installation:

pip install simple-file-checksum

Usage:

>>> from simple_file_checksum import get_checksum
>>> get_checksum("path/to/file.txt")
'9e107d9d372bb6826bd81d3542a419d6'
>>> get_checksum("path/to/file.txt", algorithm="MD5")
'9e107d9d372bb6826bd81d3542a419d6'

The SHA1, SHA256, SHA384, and SHA512 algorithms are also supported.

1 Disclosure: I am the author of simple-file-checksum.

user_63282560

change the file_path to your file

import hashlib
def getMd5(file_path):
    m = hashlib.md5()
    with open(file_path,'rb') as f:
        lines = f.read()
        m.update(lines)
    md5code = m.hexdigest()
    return md5code
user_81865190
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