Determining location of JVM executable during runtime

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How does one obtain the location of the executable of the currently running JVM during runtime? I would like to instantiate another JVM as a subprocess using the ProcessBuilder class.

I am aware that there is the java.home System property, but this doesn't specify the location of the JVM executable. I understand I could do something like this to get the path:

System.getProperties().getProperty("java.home") + File.pathSeparator + "bin" + File.pathSeparator + "java"

This code isn't platform independent, because the Windows executable's name is java.exe, not java. Is there a way to get the path of the JVM executable that takes the platform's idiosyncrasies into account?

filepath jvm java
5 Answers

Following code obtains path to current java executable by using ProcessHandle.Info of current ProcessHandle.

Result is wrapped in Optional since the access to command info may be restricted by operating system permissions.

String javaExecutablePath = ProcessHandle.current()
    .info()
    .command()
    .orElseThrow();
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