Having to go to the parent node first seems a bit odd to me, is there a reason JavaScript works like this?
The function name is removeChild(), and how is it possible to remove the child when there's no parent? :)
On the other hand, you do not always have to call it as you have shown. element.parentNode is only a helper to get the parent node of the given node. If you already know the parent node, you can just use it like this:
Ex:
// Removing a specified element when knowing its parent node
var d = document.getElementById("top");
var d_nested = document.getElementById("nested");
var throwawayNode = d.removeChild(d_nested);
https://developer.mozilla.org/en-US/docs/Web/API/Node/removeChild
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To add something more:
Some answers have pointed out that instead of using parentNode.removeChild(child);, you can use elem.remove();. But as I have noticed, there is a difference between the two functions, and it's not mentioned in those answers.
If you use removeChild(), it will return a reference to the removed node.
var removedChild = element.parentNode.removeChild(element);
console.log(removedChild); //will print the removed child.
But if you use elem.remove();, it won't return you the reference.
var el = document.getElementById('Example');
var removedChild = el.remove(); //undefined
https://developer.mozilla.org/en-US/docs/Web/API/ChildNode/remove
This behavior can be observed in Chrome and FF. I believe It's worth noticing :)
Hope my answer adds some value to the question and will be helpful!!