I'm looking for a way to pull the last characters from a String, regardless of size. Lets take these strings into example:
"abcd: efg: 1006746"
"bhddy: nshhf36: 1006754"
"hfquv: nd: 5894254"
As you can see, completely random strings, but they have 7 numbers at the end. How would I be able to take those 7 numbers?
Edit:
I just realized that String[] string = s.split(": "); would work great here, as long as I call string[2] for the numbers and string[1] for anything in the middle.
You can achieve it using this single line code :
String numbers = text.substring(text.length() - 7, text.length());
But be sure to catch Exception if the input string length is less than 7.
You can replace 7 with any number say N, if you want to get last 'N' characters.
StringUtils.substringAfterLast("abcd: efg: 1006746", ": ") = "1006746";
As long as the format of the string is fixed you can use substringAfterLast.
org.apache.commons.lang3.StringUtils.substring(s, -7)
gives you the answer. It returns the input if it is shorter than 7, and null if s == null. It never throws an exception.
E.g : "abcd: efg: 1006746" "bhddy: nshhf36: 1006754" "hfquv: nd: 5894254"
-Step 1: String firstString = "abcd: efg: 1006746";
-Step 2: String lastSevenNumber = firstString.substring(firstString.lastIndexOf(':'), firstString.length()).trim();