Java variable number of arguments for a method

That's correct. You can find more about it in the Oracle guide on varargs.

Here's an example:

void foo(String... args) {
    for (String arg : args) {
        System.out.println(arg);
    }
}

which can be called as

foo("foo"); // Single arg.
foo("foo", "bar"); // Multiple args.
foo("foo", "bar", "lol"); // Don't matter how many!
foo(new String[] { "foo", "bar" }); // Arrays are also accepted.
foo(); // And even no args.

Yes, it's possible:

public void myMethod(int... numbers) { /* your code */ }

Yup...since Java 5: http://java.sun.com/j2se/1.5.0/docs/guide/language/varargs.html

Yes Java allows vargs in method parameter .

public class  Varargs
{
   public int add(int... numbers)
   { 
      int result = 1; 
      for(int number: numbers)
      {
         result= result+number;  
      }  return result; 
   }
}