How to convert integer to char in C?

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How to convert integer to char in C?

6 Answers

A char in C is already a number (the character's ASCII code), no conversion required.

If you want to convert a digit to the corresponding character, you can simply add '0':

c = i +'0';

The '0' is a character in the ASCll table.

You can try atoi() library function. Also sscanf() and sprintf() would help.

Here is a small example to show converting integer to character string:

main()
{
  int i = 247593;
  char str[10];

  sprintf(str, "%d", i);
  // Now str contains the integer as characters
} 

Here for another Example

#include <stdio.h>

int main(void)
{
   char text[] = "StringX";
   int digit;
   for (digit = 0; digit < 10; ++digit)
   {
      text[6] = digit + '0';
      puts(text);
   }
   return 0;
}

/* my output
String0
String1
String2
String3
String4
String5
String6
String7
String8
String9
*/

Just assign the int to a char variable.

int i = 65;
char c = i;
printf("%c", c); //prints A
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