grep with regex for phone number

user_233254 0
Viewed 55001

I would like to get the phone numbers from a file. I know the numbers have different forms, I can handle for a single one, but don't know how to get a uniform regex. For example

  1. xxx-xxx-xxxx

  2. (xxx)xxx-xxxx

  3. xxx xxx xxxx

  4. xxxxxxxxxx

I can only handle 1, 2, and 4 together

grep '[0-9]\{3\}[ -]\?[0-9]\{3\}[ -]\?[0-9]\{4\}' file

Is there any one single regex can handle all of these four forms?

grep regex
11 Answers
grep '\(([0-9]\{3\})\|[0-9]\{3\}\)[ -]\?[0-9]\{3\}[ -]\?[0-9]\{4\}' file

Explanation:

([0-9]\{3\}) three digits inside parentheses

\| or

[0-9]\{3\} three digits not inside parens

...with grouping parentheses - \(...\) - around the alternation so the rest of the regex behaves the same no matter which alternative matches.

Alan_M_209380

You can just OR (|) your regexes together -- will be more readable that way too!

user_16260

My first thought is that you may find it easier to see if your candidate number matches against one of four regular expressions. That will be easier to develop/debug, especially as/when you have to handle additional formats in the future.

Brian_Agnew_129600 
grep -P '[0-9]{3}-[0-9]{3}-[0-9]{3}|[0-9]{3}\ [0-9]{3}\ [0-9]{3}|[0-9]{9}|\([0-9]{3}\)[0-9]{3}-[0-9]{3}'
user_2553120 
grep -oE '\(?\<[0-9]{3}[-) ]?[0-9]{3}[ -]?[0-9]{4}\>'

Matches all your formats.

The \< and \> word boundaries prevent matching numbers that are too long, such as 123-123-12345 or 1234-123-1234

user_75520

I got this:

debian:tmp$ cat p.txt
333-444-5555
(333)333-6666
123 456 7890
1234567890
debian:tmp$ egrep '\(?[0-9]{3}[ )-]?[0-9]{3}[ -]?[0-9]{4}' p.txt
333-444-5555
(333)333-6666
123 456 7890
1234567890
debian:tmp$ egrep --version
GNU grep 2.5.3

Copyright (C) 1988, 1992-2002, 2004, 2005  Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

debian:tmp$
user_2675420
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