Prevent class inheritance in C++

user_246894 0
Viewed 50160

Recently one of my friend asked me how to prevent class inheritance in C++. He wanted the compilation to fail.

I was thinking about it and found 3 answers. Not sure which is the best one.

1) Private Constructor(s)

class CBase
{

public:

 static CBase* CreateInstance() 
 { 
  CBase* b1 = new CBase();
  return b1;
 }

private:

 CBase() { }
 CBase(CBase3) { }
 CBase& operator=(CBase&) { }


};

2) Using CSealed base class, private ctor & virtual inheritance

class CSealed
{

private:

 CSealed() {
 }

 friend class CBase;
};


class CBase : virtual CSealed
{

public:

 CBase() {
 }

};

3) Using a CSealed base class, protected ctor & virtual inheritance

class CSealed
{

protected:

 CSealed() {
 }

};

class CBase : virtual CSealed
{

public:

 CBase() {
 }

};

All the above methods make sure that CBase class cannot be inherited further. My Question is:

  1. Which is the best method ? Any other methods available ?

  2. Method 2 & 3 will not work unless the CSealed class is inherited virutally. Why is that ? Does it have anything to do with vdisp ptr ??

PS:

The above program was compiled in MS C++ compiler (Visual Studio). reference : http://www.codeguru.com/forum/archive/index.php/t-321146.html

controls inheritance c++
9 Answers

You can't prevent inheritance (before C++11's final keyword) - you can only prevent instantiation of inherited classes. In other words, there is no way of preventing:

class A { ... };

class B : public A { ... };

The best you can do is prevent objects of type B from being instantiated. That being the case, I suggest you take kts's advice and document the fact that A (or whatever) is not intended to be used for inheritance, give it a non-virtual destructor, and no other virtual functions, and leave it at that.

Admin1

You are going through contortions to prevent further subclassing. Why? Document the fact that the class isn't extensible and make the dtor non-virtual. In the spirit of c, if someone really wants to ignore the way you intended this to be used why stop them? (I never saw the point of final classes/methods in java either).

//Note: this class is not designed to be extended. (Hence the non-virtual dtor)
struct DontExtened
{
  DontExtened();
  /*NOT VIRTUAL*/
  ~DontExtened();
  ...
};
user_865150

1) is a matter of taste. If I see it correctly, your more fancy 2nd and 3rd solutions move the error in certain circumstances from link time to compile time, which in general should be better.

2) Virtual inheritance is needed to force the responsibility to initialize the (virtual) base class to the most derived class from where the base class ctor is no longer reachable.

user_1479320

To answer your question, you can't inherit from CBase because in virtual inheritance a derived class would need to have direct access to the class from which it was inherited virtually. In this case, a class that would derive from CBase would need to have direct access to CSealed which it can't since the constructor is private.

Though I don't see the usefulness of it all (ie: stopping inheritance) you can generalize using templates (I don't think it compiles on all compilers but it does with MSVC)

template<class T>
class CSealed
{
    friend T;    // Don't do friend class T because it won't compile
    CSealed() {}
};

class CBase : private virtual CSealed<CBase>
{
};
user_2515490

If you can, I'd go for the first option (private constructor). The reason is that pretty much any experienced C++ programmer will see that at a glance and be able to recognize that you are trying to prevent subclassing.

There might be other more tricky methods to prevent subclassing, but in this case the simpler the better.

user_296390

From C++11 onward, there is a clean solution that I am surprise not to see here. We can make the class final preventing any further inheritance.

class Foo final {};

class Bar: public Foo {}; // Fails to compile as Foo is marked as final
user_35402470
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