How to set background color of a View

When you call setBackgoundColor it overwrites/removes any existing background resource, including any borders, corners, padding, etc. What you want to do is change the color of the existing background resource...

View v;
v.getBackground().setColorFilter(Color.parseColor("#00ff00"), PorterDuff.Mode.DARKEN);

Experiment with PorterDuff.Mode.* for different effects.

// set the background to green
v.setBackgroundColor(0x0000FF00 );
v.invalidate();

The code does not set the button to green. Instead, it makes the button totally invisible.

Explanation: the hex value of the color is wrong. With an Alpha value of zero, the color will be invisible.

The correct hex value is 0xFF00FF00 for full opacity green. Any Alpha value between 00 and FF would cause transparency.

and what is the correct way to change the background color on any View?

On any View? What you have is correct, though you should drop the invalidate() call.

However, some Views already have backgrounds. A Button, for example, already has a background: the face of the button itself. This background is a StateListDrawable, which you can find in android-2.1/data/res/drawable/btn_default.xml in your Android SDK installation. That, in turn, refers to a bunch of nine-patch bitmap images, available in multiple densities. You would need to clone and modify all of that to accomplish your green goals.

In short, you will be better served finding another UI pattern rather than attempting to change the background of a Button.

This question talks about changing the background color of a view. In one of the answers, the person explains how to change the background color during runtime. Obviously you are going to look into how to modify other objects on the screen, but this should give you a good start by at least allowing you to modify the background color of the view on button click.

You can simple use :

view.setBackgroundColor(Color.rgb(0, 198, 255));

This works for me

v.getBackground().setTint(Color.parseColor("#212121"));

That way only changes the color of the background without change the background itself. This is usefull for example if you have a background with rounded corners.

In kotlin you could do it like this:

val backgroundColor = R.color.whatever_color_you_like
view.setBackgroundColor(getColorCompat(backgroundColor))

Where getColorCompat() is an extension function:

/**
 * Extension method to provide simpler access to {@link ContextCompat#getColor(int)}.
 */

 fun Context.getColorCompat(color: Int) = ContextCompat.getColor(this, color)

view.setBackgroundColor(R.color.primaryColor);

Adds color to previous color value, so i have a different color.

What works for me is :

view.setBackgroundResource(R.color.primaryColor);

Let suppose we have a primary color in values=>colors.xml as:

<resources>
    <color name="primary">#FDD835</color>
</resources>

so if we want to use our custom color into setBackgroundColor(@ColorInt int Color) then we just need an annotation @SuppressLint("ResourceAsColor") with constructor/method which will be used as:

    @SuppressLint("ResourceAsColor")
    public _LinearLayout(Context context) {
        super(context);

        // Formatting our layout : )
        super.setBackgroundColor(R.color.primary);

        ....


    }

You must pass an int in the argument.

First Example:

view.setBackgroundColor(-500136)

Second Example:

int colorId = R.color.green;

view.setBackgroundResource(colorId);

This should work fine: v.setBackgroundColor(0xFF00FF00);

I tried all the above ways. But I havent achieve what i need. Here is my try. If you are using hexcode for color and want to set the color as background of image, then this is the kotlin code.

val bitmap = Bitmap.createBitmap(30, 30, Bitmap.Config.ARGB_8888)
val canvas = Canvas(bitmap)
val colorCode = "#ffffff"
canvas.drawColor(Color.parseColor(colorCode))
mImageViewLogo.setImageBitmap(bitmap)