I'm just wondering if there is a way (maybe with regex) to validate that an input on a Java desktop app is exactly a string formatted as: "YYYY-MM-DD".
I'm just wondering if there is a way (maybe with regex) to validate that an input on a Java desktop app is exactly a string formatted as: "YYYY-MM-DD".
Use the following regular expression:
^\d{4}-\d{2}-\d{2}$
as in
if (str.matches("\\d{4}-\\d{2}-\\d{2}")) {
...
}
With the matches method, the anchors ^ and $ (beginning and end of string, respectively) are present implicitly.
The pattern above checks conformance with the general “shape” of a date, but it will accept more invalid than valid dates. You may be surprised to learn that checking for valid dates — including leap years! — is possible using a regular expression, but not advisable. Borrowing from an answer elsewhere by Kuldeep, we can all find amusement and admiration for persistence in
((18|19|20)[0-9]{2}[\-.](0[13578]|1[02])[\-.](0[1-9]|[12][0-9]|3[01]))|(18|19|20)[0-9]{2}[\-.](0[469]|11)[\-.](0[1-9]|[12][0-9]|30)|(18|19|20)[0-9]{2}[\-.](02)[\-.](0[1-9]|1[0-9]|2[0-8])|(((18|19|20)(04|08|[2468][048]|[13579][26]))|2000)[\-.](02)[\-.]29
In a production context, your colleagues will appreciate a more straightforward implementation. Remember, the first rule of optimization is Don’t!
You need more than a regex, for example "9999-99-00" isn't a valid date. There's a SimpleDateFormat class that's built to do this. More heavyweight, but more comprehensive.
e.g.
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
boolean isValidDate(string input) {
try {
format.parse(input);
return true;
}
catch(ParseException e){
return false;
}
}
Unfortunately, SimpleDateFormat is both heavyweight and not thread-safe.
Putting it all together:
REGEX doesn't validate values (like "2010-19-19") SimpleDateFormat does not check format ("2010-1-2", "1-0002-003" are accepted) it's necessary to use both to validate format and value:
public static boolean isValid(String text) {
if (text == null || !text.matches("\\d{4}-[01]\\d-[0-3]\\d"))
return false;
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd");
df.setLenient(false);
try {
df.parse(text);
return true;
} catch (ParseException ex) {
return false;
}
}
private static final ThreadLocal<SimpleDateFormat> format = new ThreadLocal<SimpleDateFormat>() {
@Override
protected SimpleDateFormat initialValue() {
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd");
df.setLenient(false);
System.out.println("created");
return df;
}
};
public static boolean isValid(String text) {
if (text == null || !text.matches("\\d{4}-[01]\\d-[0-3]\\d"))
return false;
try {
format.get().parse(text);
return true;
} catch (ParseException ex) {
return false;
}
}
(same can be done for a Matcher, that also is not thread safe)
The following regex will accept YYYY-MM-DD (within the range 1600-2999 year) formatted dates taking into consideration leap years:
^((?:(?:1[6-9]|2[0-9])\d{2})(-)(?:(?:(?:0[13578]|1[02])(-)31)|((0[1,3-9]|1[0-2])(-)(29|30))))$|^(?:(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))(-)02(-)29)$|^(?:(?:1[6-9]|2[0-9])\d{2})(-)(?:(?:0[1-9])|(?:1[0-2]))(-)(?:0[1-9]|1\d|2[0-8])$
Examples:
You can test it here.
Note: if you want to accept one digit as month or day you can use:
^((?:(?:1[6-9]|2[0-9])\d{2})(-)(?:(?:(?:0?[13578]|1[02])(-)31)|((0?[1,3-9]|1[0-2])(-)(29|30))))$|^(?:(?:(?:(?:1[6-9]|[2-9]\d)?(?:0[48]|[2468][048]|[13579][26])|(?:(?:16|[2468][048]|[3579][26])00)))(-)0?2(-)29)$|^(?:(?:1[6-9]|2[0-9])\d{2})(-)(?:(?:0?[1-9])|(?:1[0-2]))(-)(?:0?[1-9]|1\d|2[0-8])$
I have created the above regex starting from this solution
Construct a SimpleDateFormat with the mask, and then call: SimpleDateFormat.parse(String s, ParsePosition p)
For fine control, consider an InputVerifier using the SimpleDateFormat("YYYY-MM-dd") suggested by Steve B.
Below added code is working for me if you are using pattern dd-MM-yyyy.
public boolean isValidDate(String date) {
boolean check;
String date1 = "^(0?[1-9]|[12][0-9]|3[01])-(0?[1-9]|1[012])-([12][0-9]{3})$";
check = date.matches(date1);
return check;
}
If you want a simple regex then it won't be accurate. https://www.freeformatter.com/java-regex-tester.html#ad-output offers a tool to test your Java regex. Also, at the bottom you can find some suggested regexes for validating a date.
ISO date format (yyyy-mm-dd):
^[0-9]{4}-(((0[13578]|(10|12))-(0[1-9]|[1-2][0-9]|3[0-1]))|(02-(0[1-9]|[1-2][0-9]))|((0[469]|11)-(0[1-9]|[1-2][0-9]|30)))$
ISO date format (yyyy-mm-dd) with separators '-' or '/' or '.' or ' '. Forces usage of same separator accross date.
^[0-9]{4}([- /.])(((0[13578]|(10|12))\1(0[1-9]|[1-2][0-9]|3[0-1]))|(02\1(0[1-9]|[1-2][0-9]))|((0[469]|11)\1(0[1-9]|[1-2][0-9]|30)))$
United States date format (mm/dd/yyyy)
^(((0[13578]|(10|12))/(0[1-9]|[1-2][0-9]|3[0-1]))|(02/(0[1-9]|[1-2][0-9]))|((0[469]|11)/(0[1-9]|[1-2][0-9]|30)))/[0-9]{4}$
Hours and minutes, 24 hours format (HH:MM):
^(20|21|22|23|[01]\d|\d)((:[0-5]\d){1,2})$
Good luck