How to access specific raw data on disk from java

user_178973 0
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I'm trying to use the following code to access one byte with offset of 50 bytes in a raw disk.

randomAccessFile = new RandomAccessFile("C:", "r");
randomAccessFile.seek(50);
byte[] buffer = new byte[1];
randomAccessFile.read(buffer);

But all what I get is the following error:

java.io.FileNotFoundException: C: (Acceso denegado)
at java.io.RandomAccessFile.open(Native Method)
at java.io.RandomAccessFile.<init>(RandomAccessFile.java:212)
at java.io.RandomAccessFile.<init>(RandomAccessFile.java:98)
at pru.lseek.main(lseek.java:26)

Is there any way to access a precise byte in a drive from java?

drive java
8 Answers

RandomAccessFile is not meant to open directories to manipulate entries, you need to create or remove files. "Acceso denegado" probably mean access denied. To do this anyway you need JNI.

EDIT: What you are trying to do, is really complicated, there is no common way to do that. You can access the harddisc sector by sector, but then you would have to interpret it's structure, which obviously depends on the file system, FAT,NTFS,HPFS etc.

user_2415900

Under Linux you can try to open /dev/<device>, e.g. /dev/hda, or /dev/sdb2. This will give you access to a raw disk (or a partition only) but requires that you have appropriate rights—a “normal” user does not have them, though.

user_435820

Java can only access files. Unix has the concept of "raw devices" as files in the /dev directory, so what you want is possible there. But not on windows, because it has no such file representation of the raw HD data.

user_168830

In windows you need to access the raw device identifier as a file. It should work if you pass in the file "\\.\c:", you are using the device UNC name \.\c: (\. means this machine).

For Vista and later I don't think it will work correctly as there are mechanisms in place to prevent raw access to the disk for anything other than device drivers (don't quote me on that)

Petesh_178330
user_418030
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