Appending the same string to a list of strings in Python

The simplest way to do this is with a list comprehension:

[s + mystring for s in mylist]

Notice that I avoided using builtin names like list because that shadows or hides the builtin names, which is very much not good.

Also, if you do not actually need a list, but just need an iterator, a generator expression can be more efficient (although it does not likely matter on short lists):

(s + mystring for s in mylist)

These are very powerful, flexible, and concise. Every good python programmer should learn to wield them.

my_list = ['foo', 'fob', 'faz', 'funk']
string = 'bar'
my_new_list = [x + string for x in my_list]
print my_new_list

This will print:

['foobar', 'fobbar', 'fazbar', 'funkbar']

Here is a simple answer using pandas.

import pandas as pd
list1 = ['foo', 'fob', 'faz', 'funk']
string = 'bar'

list2 = (pd.Series(list1) + string).tolist()
list2
# ['foobar', 'fobbar', 'fazbar', 'funkbar']

Updating with more options

Below are some of the methods I have followed, and I'm sure there could be more.

Method 1:

list1 = ['foo', 'fob', 'faz', 'funk']
list2 = [ls+"bar" for ls in list1] # using list comprehension
print(list2)

Method 2:

list1 = ['foo', 'fob', 'faz', 'funk']
list2 = list(map(lambda ls: ls+"bar", list1))
print(list2)

Method 3:

list1 = ['foo', 'fob', 'faz', 'funk']
addstring = 'bar'
for index, value in enumerate(list1):
    list1[index] = addstring + value #this will prepend the string
    #list1[index] = value + addstring #this will append the string

Method 4:

list1 = ['foo', 'fob', 'faz', 'funk']
addstring = 'bar'
list2 = []
for value in list1:
    list2.append(str(value) + "bar")
print(list2)

Method 5:

list1 = ['foo', 'fob', 'faz', 'funk']
list2 = list(map(''.join, zip(list1, ["bar"]*len(list1))))
print(list2)

Avoid using keywords as variables like 'list', renamed 'list' as 'list1' instead

Combining map and format:

>>> list(map('{}bar'.format,  ['foo', 'fob', 'faz', 'funk']))
['foobar', 'fobbar', 'fazbar', 'funkbar']

Thus, there is no loop variable.
It works for Python 2 and 3. (In Python 3 one can write [*map(...)], and in Python 2 just map(...).

Extending a bit to "Appending a list of strings to a list of strings":

    import numpy as np
    lst1 = ['a','b','c','d','e']
    lst2 = ['1','2','3','4','5']

    at = np.full(fill_value='@',shape=len(lst1),dtype=object) #optional third list
    result = np.array(lst1,dtype=object)+at+np.array(lst2,dtype=object)

Result:

array(['a@1', 'b@2', 'c@3', 'd@4', 'e@5'], dtype=object)

dtype odject may be further converted str

list2 = ['%sbar' % (x,) for x in list]

And don't use list as a name; it shadows the built-in type.

new_list = [word_in_list + end_string for word_in_list in old_list]

Using names such as "list" for your variable names is bad since it will overwrite/override the builtins.

Just in case

list = ['foo', 'fob', 'faz', 'funk']
string = 'bar'
for i in range(len(list)):
    list[i] += string
print(list)