For instance, %11.2lf in C++ becomes %11.2f in Java.
How about for long format?
C++ Equivalent of %ld in Java for String.format()
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2 Answers
As you may have worked out, it's not necessary to specify the l flag. According to the docs, a decimal integer is specified by d just like in C++. So the answer is just %d.
Use %d for decimals (long, int). It works OK. E.g.:
System.err.println(String.format("%d", 193874120937489387L));
...will print just fine. Read up on java.util.Formatter for more details. %d will take a long, no problem.
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