To identify each devices uniquely I would like to use the IMEI (or ESN number for CDMA devices). How to access this programmatically?
22 Answers
You want to call android.telephony.TelephonyManager.getDeviceId().
This will return whatever string uniquely identifies the device (IMEI on GSM, MEID for CDMA).
You'll need the following permission in your AndroidManifest.xml:
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
in order to do this.
That being said, be careful about doing this. Not only will users wonder why your application is accessing their telephony stack, it might be difficult to migrate data over if the user gets a new device.
Update: As mentioned in the comments below, this is not a secure way to authenticate users, and raises privacy concerns. It is not recommended. Instead, look at the Google+ Login API if you want to implement a frictionless login system.
The Android Backup API is also available if you just want a lightweight way to persist a bundle of strings for when a user resets their phone (or buys a new device).
Try this(need to get first IMEI always)
TelephonyManager mTelephony = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (ActivityCompat.checkSelfPermission(LoginActivity.this,Manifest.permission.READ_PHONE_STATE)!= PackageManager.PERMISSION_GRANTED) {
return;
}
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
if (mTelephony.getPhoneCount() == 2) {
IME = mTelephony.getImei(0);
}else{
IME = mTelephony.getImei();
}
}else{
if (mTelephony.getPhoneCount() == 2) {
IME = mTelephony.getDeviceId(0);
} else {
IME = mTelephony.getDeviceId();
}
}
} else {
IME = mTelephony.getDeviceId();
}
The method getDeviceId() is deprecated.
There a new method for this getImei(int)
You'll need the following permission in your AndroidManifest.xml:
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
To get IMEI (international mobile equipment identifier) and if It is above API level 26 then we get telephonyManager.getImei() as null so for that, we use ANDROID_ID as a Unique Identifier.
public static String getIMEINumber(@NonNull final Context context)
throws SecurityException, NullPointerException {
TelephonyManager tm = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
String imei;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
assert tm != null;
imei = tm.getImei();
//this change is for Android 10 as per security concern it will not provide the imei number.
if (imei == null) {
imei = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
} else {
assert tm != null;
if (tm.getDeviceId() != null && !tm.getDeviceId().equals("000000000000000")) {
imei = tm.getDeviceId();
} else {
imei = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
}
}
return imei;
}
Kotlin Code for getting DeviceId ( IMEI ) with handling permission & comparability check for all android versions :
val telephonyManager = getSystemService(Context.TELEPHONY_SERVICE) as TelephonyManager
if (ContextCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE)
== PackageManager.PERMISSION_GRANTED) {
// Permission is granted
val imei : String? = if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) telephonyManager.imei
// older OS versions
else telephonyManager.deviceId
imei?.let {
Log.i("Log", "DeviceId=$it" )
}
} else { // Permission is not granted
}
Also add this permission to AndroidManifest.xml :
<uses-permission android:name="android.permission.READ_PHONE_STATE"/> <!-- IMEI-->
use below code:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
String[] permissions = {Manifest.permission.READ_PHONE_STATE};
if (ActivityCompat.checkSelfPermission(this,
Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
requestPermissions(permissions, READ_PHONE_STATE);
}
} else {
try {
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return;
}
String imei = telephonyManager.getDeviceId();
} catch (Exception e) {
e.printStackTrace();
}
}
And call onRequestPermissionsResult method following code:
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
switch (requestCode) {
case READ_PHONE_STATE:
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED)
try {
TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) != PackageManager.PERMISSION_GRANTED) {
return;
}
String imei = telephonyManager.getDeviceId();
} catch (Exception e) {
e.printStackTrace();
}
}
}
Add following permission in your AndroidManifest.xml:
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
For Android 10 Following code is working for me.
val uid: String = Settings.Secure.getString(ctx.applicationContext.contentResolver, Settings.Secure.ANDROID_ID)
if (ContextCompat.checkSelfPermission(ctx, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
imei = when {
Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q -> {
uid
}
Build.VERSION.SDK_INT >= Build.VERSION_CODES.O -> {
telephonyManager.imei
}
else -> {
telephonyManager.deviceId
}
}
}
For those looking for a Kotlin version, you can use something like this;
private fun telephonyService() {
val telephonyManager = getSystemService(TELEPHONY_SERVICE) as TelephonyManager
val imei = if (android.os.Build.VERSION.SDK_INT >= 26) {
Timber.i("Phone >= 26 IMEI")
telephonyManager.imei
} else {
Timber.i("Phone IMEI < 26")
telephonyManager.deviceId
}
Timber.i("Phone IMEI $imei")
}
NOTE: You must wrap telephonyService() above with a permission check using checkSelfPermission or whatever method you use.
Also add this permission in the manifest file;
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
There is no Way you can get imei number from andorid 10+ or 29+ mobiles here is the alternative function that will be used for creating imei number for devices.
public static String getDeviceID(){
String devIDShort = "35" + //we make this look like a valid IMEI
Build.BOARD.length()%10+ Build.BRAND.length()%10 +
Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 +
Build.DISPLAY.length()%10 + Build.HOST.length()%10 +
Build.ID.length()%10 + Build.MANUFACTURER.length()%10 +
Build.MODEL.length()%10 + Build.PRODUCT.length()%10 +
Build.TAGS.length()%10 + Build.TYPE.length()%10 +
Build.USER.length()%10 ; //13 digits
return devIDShort;
}
Restriction on non-resettable device identifiers
Starting in Android 10, apps must have the READ_PRIVILEGED_PHONE_STATE privileged permission in order to access the device's non-resettable identifiers, which include both IMEI and serial number.
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