How do you remove an array element in a foreach loop?

user_206446 0
Viewed 171496

I want to loop through an array with foreach to check if a value exists. If the value does exist, I want to delete the element which contains it.

I have the following code:

foreach($display_related_tags as $tag_name) {
    if($tag_name == $found_tag['name']) {
        // Delete element
    }
}

I don't know how to delete the element once the value is found. How do I delete it?

I have to use foreach for this problem. There are probably alternatives to foreach, and you are welcome to share them.

foreach arrays loops php
6 Answers

If you also get the key, you can delete that item like this:

foreach ($display_related_tags as $key => $tag_name) {
    if($tag_name == $found_tag['name']) {
        unset($display_related_tags[$key]);
    }
}
Gumbo_531140 
foreach($display_related_tags as $key => $tag_name)
{
    if($tag_name == $found_tag['name'])
        unset($display_related_tags[$key];
}
user_2344220

Instead of doing foreach() loop on the array, it would be faster to use array_search() to find the proper key. On small arrays, I would go with foreach for better readibility, but for bigger arrays, or often executed code, this should be a bit more optimal:

$result=array_search($unwantedValue,$array,true);
if($result !== false) {
  unset($array[$result]);   
}

The strict comparsion operator !== is needed, because array_search() can return 0 as the index of the $unwantedValue.

Also, the above example will remove just the first value $unwantedValue, if the $unwantedValue can occur more then once in the $array, You should use array_keys(), to find all of them:

$result=array_keys($array,$unwantedValue,true)
foreach($result as $key) {
  unset($array[$key]);
}

Check http://php.net/manual/en/function.array-search.php for more information.

user_2372150
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