Convert integer into byte array (Java)

Have a look at the ByteBuffer class.

ByteBuffer b = ByteBuffer.allocate(4);
//b.order(ByteOrder.BIG_ENDIAN); // optional, the initial order of a byte buffer is always BIG_ENDIAN.
b.putInt(0xAABBCCDD);

byte[] result = b.array();

Setting the byte order ensures that result[0] == 0xAA, result[1] == 0xBB, result[2] == 0xCC and result[3] == 0xDD.

Or alternatively, you could do it manually:

byte[] toBytes(int i)
{
  byte[] result = new byte[4];

  result[0] = (byte) (i >> 24);
  result[1] = (byte) (i >> 16);
  result[2] = (byte) (i >> 8);
  result[3] = (byte) (i /*>> 0*/);

  return result;
}

The ByteBuffer class was designed for such dirty hands tasks though. In fact the private java.nio.Bits defines these helper methods that are used by ByteBuffer.putInt():

private static byte int3(int x) { return (byte)(x >> 24); }
private static byte int2(int x) { return (byte)(x >> 16); }
private static byte int1(int x) { return (byte)(x >>  8); }
private static byte int0(int x) { return (byte)(x >>  0); }

Using BigInteger:

private byte[] bigIntToByteArray( final int i ) {
    BigInteger bigInt = BigInteger.valueOf(i);      
    return bigInt.toByteArray();
}

Using DataOutputStream:

private byte[] intToByteArray ( final int i ) throws IOException {      
    ByteArrayOutputStream bos = new ByteArrayOutputStream();
    DataOutputStream dos = new DataOutputStream(bos);
    dos.writeInt(i);
    dos.flush();
    return bos.toByteArray();
}

Using ByteBuffer:

public byte[] intToBytes( final int i ) {
    ByteBuffer bb = ByteBuffer.allocate(4); 
    bb.putInt(i); 
    return bb.array();
}

You can use BigInteger:

From Integers:

byte[] array = BigInteger.valueOf(0xAABBCCDD).toByteArray();
System.out.println(Arrays.toString(array))
// --> {-86, -69, -52, -35 }

The returned array is of the size that is needed to represent the number, so it could be of size 1, to represent 1 for example. However, the size cannot be more than four bytes if an int is passed.

From Strings:

BigInteger v = new BigInteger("AABBCCDD", 16);
byte[] array = v.toByteArray();

However, you will need to watch out, if the first byte is higher 0x7F (as is in this case), where BigInteger would insert a 0x00 byte to the beginning of the array. This is needed to distinguish between positive and negative values.

Can also shift -

byte[] ba = new byte[4];
int val = Integer.MAX_VALUE;

for(byte i=0;i<4;i++)
    ba[i] = (byte)(val >> i*8);
    //ba[3-i] = (byte)(val >> i*8); //Big-endian

Simple solution which properly handles ByteOrder:

ByteBuffer.allocate(4).order(ByteOrder.nativeOrder()).putInt(yourInt).array();

very easy with android

int i=10000;
byte b1=(byte)Color.alpha(i);
byte b2=(byte)Color.red(i);
byte b3=(byte)Color.green(i);
byte b4=(byte)Color.blue(i);