Grep and Python

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I need a way of searching a file using grep via a regular expression from the Unix command line. For example when I type in the command line:

python pythonfile.py 'RE' 'file-to-be-searched'

I need the regular expression 'RE' to be searched in the file and print out the matching lines.

Here's the code I have:

import re
import sys

search_term = sys.argv[1]
f = sys.argv[2]

for line in open(f, 'r'):
    if re.search(search_term, line):
        print line,
        if line == None:
            print 'no matches found'

But when I enter a word which isn't present, no matches found doesn't print

8 Answers

The natural question is why not just use grep?! But assuming you can't...

import re
import sys

file = open(sys.argv[2], "r")

for line in file:
     if re.search(sys.argv[1], line):
         print line,

Things to note:

  • search instead of match to find anywhere in string
  • comma (,) after print removes carriage return (line will have one)
  • argv includes python file name, so variables need to start at 1

This doesn't handle multiple arguments (like grep does) or expand wildcards (like the Unix shell would). If you wanted this functionality you could get it using the following:

import re
import sys
import glob

for arg in sys.argv[2:]:
    for file in glob.iglob(arg):
        for line in open(file, 'r'):
            if re.search(sys.argv[1], line):
                print line,

Adapted from a grep in python.

Accepts a list of filenames via [2:], does no exception handling:

#!/usr/bin/env python
import re, sys, os

for f in filter(os.path.isfile, sys.argv[2:]):
    for line in open(f).readlines():
        if re.match(sys.argv[1], line):
            print line

sys.argv[1] resp sys.argv[2:] works, if you run it as an standalone executable, meaning

chmod +x

first

  1. use sys.argv to get the command-line parameters
  2. use open(), read() to manipulate file
  3. use the Python re module to match lines

The real problem is that the variable line always has a value. The test for "no matches found" is whether there is a match so the code "if line == None:" should be replaced with "else:"

You can use python-textops3 :

from textops import *

print('\n'.join(cat(f) | grep(search_term)))

with python-textops3 you can use unix-like commands with pipes

Not sure if your question was clear to me but to fix your code just change your if expression like the following:

import re
import sys

search_term = sys.argv[1]
f = sys.argv[2]
r = None
n = 0
for line in open(f, 'r'):
    n=n+1
    r = re.search(search_term, line)
    if r:
        print(f"{line} found at line {n}")
if not r:
    print('no matches found')

PS: I tested it on Python 3.8.10

if you want to use grep you could

grep -E '(.*)word(.*)' file.txt || echo "pattern not found"
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