Select distinct values from 1 column

user_233388 0
Viewed 91029

I want to select distinct values from only one column (the BoekingPlaatsId column) with this query: 

SELECT MAX(BoekingPlaatsId), BewonerId, Naam, VoorNaam
FROM table
GROUP BY BewonerId, Naam, VoorNaam

How do I do that in SQL Server?

distinct sql-server-2005 sql-server sql
9 Answers

DISTINCT should work if you just want the user names:

SELECT DISTINCT BewonerId, Naam, Voornaam
FROM TBL

but if you need the minimum ID values, group by the names...

SELECT MIN(BoekingPlaatsId), MIN(BewonerId), Naam, Voornaam
FROM TBL
GROUP BY Naam, Voornaam
user_1992890

I think you should be able to use

SELECT DISTINCT BewonerId, Naam, VoorNaam

You can't add BoekingPlaatsId, because:

  • DISTINCT looks for unique rows
  • You need to specify what BoekingPlaatsId value you want
    (In case of Jan Janssens, do you want BoekingPlaatsId 1 or 2?)

What also works is this:

SELECT MAX(BoekingPlaatsId), BewonerId, Naam, VoorNaam
FROM ...
GROUP BY BewonerId, Naam, VoorNaam
user_55550

I don't do alot of this so i'm not 100% certain of the syntax so you may need to tweak it slightly, google rank over and partition. Try this...

SELECT 
    *,
    RANK() OVER(PARTITION BY Naam  order by Naam ) as Rank
FROM
    TABLE
WHERE 
    Rank = 1

This is overkill for a 4 column table, but if you have a fairly denormalised table with alot of columns, this approach is invaluable for select distinct on 1 column.

user_2202990

just group By those 2 columns

  Select Min(BoekingPlaatsId), Min(bewonerId), naam, voornaam
  from table
  group By naam, voornaam
user_326320 
select Naam, Voornaam, min(BewonerId), min(BoekingPlaatsId) from tableName
group by Naam, Voornaam
user_84110

I think what you're looking for is something like this:

select distinct column1 from table1 where column2 = (select distinct column2 from table1)
user_2372290

Sounds like you want something like

select distinct(BewonerId), Naam, Voornaam from table_name
user_20350
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