Jquery - How to get the style display attribute "none / block"

user_24958 0
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Is there a way to get the style: display attribute which would have either none or block?

DIV :

<div id="ctl00_MainContentAreaPlaceHolder_cellPhone_input_msg_container" class="Error cellphone" style="display: block;">

     <p class="cellphone" style="display: block;">Text</p>

</div>

I know that there is a way to find out if the DIV is hidden or not but in my case this div is dynamically injected so it always shows up as visible false thus I cannot use that :

$j('.Error .cellphone').is(':hidden')

I am able to get the result "display:block" using :

$j('div.contextualError.ckgcellphone').attr('style')

Is there a way to get just the value "block" or "none" or is there a better/more efficient way to do this?

coding-style attributes jquery
5 Answers
//animated show/hide

function showHide(id) {
      var hidden= ("none" == $( "#".concat(id) ).css("display"));
      if(hidden){
          $( "#".concat(id) ).show(1000);
      }else{
          $("#".concat(id) ).hide(1000);
      }
  }
user_92051010
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