Java: Finding the highest value in an array

user_188122 0
Viewed 298838

For some reason this code is printing three values for the highest value in the array when I'm trying to print just one (which is 11.3). Can someone please explain to me why it is doing this?

Thanks.

import java.util.Scanner;

public class Slide24
{
    public static void main (String [] args)
    {
        Scanner in = new Scanner(System.in);

        double[] decMax = {-2.8, -8.8, 2.3, 7.9, 4.1, -1.4, 11.3, 10.4,
            8.9, 8.1, 5.8, 5.9, 7.8, 4.9, 5.7, -0.9, -0.4, 7.3, 8.3, 6.5, 9.2,
            3.5, 3, 1.1, 6.5, 5.1, -1.2, -5.1, 2, 5.2, 2.1};

        double total = 0, avgMax = 0;

        for (int counter = 0; counter < decMax.length; counter++)
        {
         total += decMax[counter];
        }

        avgMax = total / decMax.length;

        System.out.printf("%s %2.2f\n", "The average maximum temperature for December was: ", avgMax);

        //finds the highest value
        double max = decMax[0];

        for (int counter = 1; counter < decMax.length; counter++)
        {
         if (decMax[counter] > max)
         {
          max = decMax[counter];
          System.out.println("The highest maximum for the December is: " + max);
         }

        }        
    }
}
max arrays java
19 Answers

Same as suggested by others, just mentioning the cleaner way of doing it:

int max = decMax[0];
for(int i=1;i<decMax.length;i++)
    max = Math.max(decMax[i],max);
System.out.println("The Maximum value is : " + max);
user_14622820

If you don't want to use any java predefined libraries then below is the

simplest way

   public class Test {

    public static void main(String[] args) {
        double[] decMax = {-2.8, -8.8, 2.3, 7.9, 4.1, -1.4, 11.3, 10.4,
            8.9, 8.1, 5.8, 5.9, 7.8, 4.9, 5.7, -0.9, -0.4, 7.3, 8.3, 6.5, 9.2,
            3.5, 3, 1.1, 6.5, 5.1, -1.2, -5.1, 2, 5.2, 2.1};

        double maxx = decMax[0];

        for (int i = 0; i < decMax.length; i++) {
            if (maxx < decMax[i]) {
                maxx = decMax[i];
            }
        }
        System.out.println(maxx);

    }
}
user_100967140

You can write like this.

import java.util.Scanner;
class   BigNoArray{

    public static void main(String[] args){
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter how many array element");
        int n=sc.nextInt();
        int[] ar= new int[n];
        System.out.println("enter "+n+" values");
        for(int i=0;i<ar.length;i++){
            ar[i]=sc.nextInt();
        }
        int fbig=ar[0];
        int sbig=ar[1];
        int tbig=ar[3];
            for(int i=1;i<ar.length;i++){
                if(fbig<ar[i]){
                    sbig=fbig;
                    fbig=ar[i];
                }
                else if(sbig<ar[i]&&ar[i]!=fbig){
                    sbig=ar[i];
                }
                else if(tbig<ar[i]&&ar[i]!=fbig){
                    tbig=ar[i];
                }
            }
        System.out.println("first big number is "+fbig);
        System.out.println("second big number is "+sbig);
        System.out.println("third big number is "+tbig);
    }
}
user_85851460

You are just Compare zeroth element with rest of the elements so it will print the value last largest value which it will contain, in you case, same problem is happening. To compare each and every elements we have to swap the values like:

double max = decMax[0];
    for (int counter = 1; counter < decMax.length; counter++){
        if(max<decMax[i]){
            max=decMax[i]; //swapping
            decMax[i]=decMax[0];
        }
    }
    System.out.println("The max value is "+ max);

Hope this will help you

user_84655300

Easiest way which I've found, supports all android versions

Arrays.sort(series1Numbers);

int maxSeries = Integer.parseInt(String.valueOf(series1Numbers[series1Numbers.length-1]));
user_39528850

An easy way without using collections

public void findHighestNoInArray() {
        int[] a = {1,2,6,8,9};
        int large = a[0];
            for(int num : a) {
                if(large < num) {
                    large = num;
                }
            }
            System.out.println("Large number is "+large+"");
        }
user_67996340 
import java.util.*;
class main9 //Find the smallest and 2lagest and  ascending and descending order of  elements in array//
{
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        System.out.println("Enter the array range");
        int no=sc.nextInt();
        System.out.println("Enter the array element");
        int a[]=new int[no];
        int i;
        for(i=0;i<no;i++)
        {
            a[i]=sc.nextInt();
        }
        Arrays.sort(a);
        int s=a[0];
        int l=a[a.length-1];
        int m=a[a.length-2];
        System.out.println("Smallest no is="+s);
        System.out.println("lagest 2 numbers are=");
        System.out.println(l);
        System.out.println(m);
        System.out.println("Array in ascending:");
        for(i=0;i<no;i++)
        {
            System.out.println(a[i]);
        }
        System.out.println("Array in descending:");
        for(i=a.length-1;i>=0;i--)
        {
            System.out.println(a[i]);
        }
    }
}
user_113769080

simple way find max number

   int arr[] = {10, 11, 12, 13, 55, 18, 20};
    int num = arr.length;
    int max = 0;

    for (int i = 0; i < num; i++) {
        if (arr[i] > max) {
            max = arr[i];

        }

    }
    System.out.println(max);
user_140454840 
    package Loops;
    import java.util.Scanner;
    public class LargestNumber {
        public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            System.out.println("How many numbers you want to enter?\n");
            int x = sc.nextInt();
            int[] data = new int[x];
            for (int i = 0; i < data.length; i++) {
                System.out.println("Enter the number " + (i + 1));
                data[i] = sc.nextInt();
            }
            int max = data[0];
            int min = data[0];
            int i;
            for (i = 1; i < data.length; i++) {
                if (data[i] > max) {
                    max = data[i];
                } else if (data[i] < min) {
                    min = data[i];
                }
            }
            System.out.println("The highest number in array is: " + max);
            System.out.println("The smallest number in array is: " + min);
        }
    }
user_62801350 
    int[] data2 = {1,10,50,70};
    List<Integer> testing= new ArrayList<>();
    for(int s=0;s<data.length;s++){
        testing.add(data[s]);
                }
    int t= Collections.max(testing);
    int mini= Collections.min(testing);
    System.out.println("Max is:"+t);
    System.out.println("Minimum  is:"+mini);
user_62801350 
function maxElement(values){
  var max = values[0]; // Initialize maximum element
  for (value of values){ //Traverse array elements from second and compare every element with curr`enter code here`ent max 
    if (value > max) {
      max = value //new maximum
    }
  }
  return max;
}
user_171893990
Related